A256302
Least prime p such that p+3*k*(k+1) is prime for all k=0,...,n.
Original entry on oeis.org
2, 5, 5, 5, 11, 11, 11, 11, 11, 11, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23, 23
Offset: 0
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a(n)=forprime(p=1,,for(i=1,n,ispseudoprime(p+3*(i+1)*i)||next(2));return(p))
A284043
Starts of a run of at least n consecutive numbers k for which k^2 - k + 41 is composite.
Original entry on oeis.org
41, 41, 122, 162, 299, 326, 326, 1064, 1064, 1064, 1064, 1064, 5664, 5664, 5664, 5664, 9265, 9265, 9265, 22818, 22818, 37784, 37784, 47494, 100202, 100202, 100202, 167628, 167628, 167628, 167628, 167628, 167628, 167628, 167628, 176956, 176956, 176956, 1081297
Offset: 1
The values of f(n)=n^2-n+41 at 122, 123 and 124 are: 14803 = 113*131, 15047 = 41*367 and 15293 = 41*373. This is the first case of 3 consecutive composite values, thus a(3) = 122.
- Thomas Koshy, Elementary Number Theory with Applications, Academic Press, 2nd edition, 2007, Chapter 2, p. 147, exercise 50.
- Amiram Eldar, Table of n, a(n) for n = 1..130 (terms below 10^10)
- Sidney Kravitz, Problem 527, Mathematics Magazine, Vol. 36, No. 4 (1963), p. 264.
- Lawrence A. Ringenberg et al., A Prime Generator, Solutions to Problem 527, Mathematics Magazine, Vol. 37, No. 2 (1964), pp. 122-123.
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f[n_] := n^2 - n + 41; a = PrimeQ[f[Range[1, 10^7]]]; b = Split[a]; c = Length /@ b; d = Accumulate[c]; nc = Length[c]; e = {}; For[len = 0, len < 100, len++; k = 2; While[k <= nc && c[[k]] < len, k += 2]; If[k <= nc && c[[k]] >= len, ind = d[[k - 1]] + 1; e = AppendTo[e, ind]]]; e
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