cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A295067 Solution of the complementary equation a(n) = 2*a(n-2) + b(n-2), where a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 5, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

1, 3, 4, 11, 14, 29, 36, 67, 82, 146, 177, 307, 370, 631, 758, 1281, 1536, 2583, 3094, 5189, 6212, 10403, 12450, 20833, 24928, 41696, 49887, 83424, 99807, 166882, 199649, 333801, 399336, 667641, 798712, 1335323, 1597466, 2670689, 3194976, 5341423, 6389998
Offset: 0

Views

Author

Clark Kimberling, Nov 19 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.
The sequence a(n+1)/a(n) appears to have two convergent subsequences, with limits 1.19..., 1.67...

Examples

			a(0) = 1, a(1) = 3, a(2) = 3, b(0) = 2, b(1) = 5
a(2) = 2*a(0) + b(0) = 4
Complement: (b(n)) = (2, 5, 6, 7, 8, 9, 10, 12, 13, 15, ... )
		

Crossrefs

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 1; a[1] = 3; b[0] = 2; b[1]=5;
    a[n_] := a[n] = 2 a[n - 2] + b[n - 2];
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295067 *)
    Table[b[n], {n, 0, 10}]

A295068 Solution of the complementary equation a(n) = 2*a(n-2) - b(n-1) + n, where a(0) = 4, a(1) = 5, b(0) = 1, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

4, 5, 8, 10, 14, 18, 25, 32, 46, 60, 87, 115, 169, 224, 332, 442, 658, 878, 1310, 1749, 2613, 3491, 5219, 6975, 10431, 13942, 20854, 27876, 41700, 55744, 83392, 111480, 166776, 222952, 333544, 445896, 667080, 891784, 1334151, 1783559, 2668293, 3567109
Offset: 0

Views

Author

Clark Kimberling, Nov 19 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.
The sequence a(n+1)/a(n) appears to have two convergent subsequences, with limits 1.33..., 1.49...

Examples

			a(0) = 4, a(1) = 5, b(0) = 1
a(2) = 2*a(0) - b(1)  + 2 = 8
Complement: (b(n)) = (1, 2, 3, 6, 7, 9, 11, 12, 13, 15, 16, 17, 19, ... )
		

Crossrefs

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 4; a[1] = 5; b[0] = 1;
    a[n_] := a[n] = 2 a[n - 2] - b[n - 1] + n;
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295068 *)
    Table[b[n], {n, 0, 10}]

A295069 Solution of the complementary equation a(n) = 2*a(n-2) - b(n-2) + n, where a(0) = 3, a(1) = 4, b(0) = 1, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

3, 4, 7, 9, 13, 17, 24, 31, 45, 59, 86, 114, 168, 223, 331, 441, 657, 877, 1309, 1748, 2612, 3490, 5218, 6974, 10430, 13941, 20853, 27875, 41699, 55743, 83391, 111479, 166775, 222951, 333543, 445895, 667079, 891783, 1334150, 1783558, 2668292, 3567108
Offset: 0

Views

Author

Clark Kimberling, Nov 19 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.
The sequence a(n+1)/a(n) appears to have two convergent subsequences, with limits 1.33..., 1.49...

Examples

			a(0) = 3, a(1) = 4, b(0) = 1
a(2) = 2*a(0) - b(0)  + 2 = 7
Complement: (b(n)) = (1, 2, 5, 6, 8, 10, 11, 12, 14, 15, 16, 18, ... )
		

Crossrefs

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 3; a[1] = 4; b[0] = 1;
    a[n_] := a[n] = 2 a[n - 2] + b[n - 1] + n;
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295069 *)
    Table[b[n], {n, 0, 10}]

A295054 Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(1) + b(2) + ... + b(n-1), where a(0) = 1, a(1) = 2, b(0) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

1, 2, 7, 18, 40, 81, 153, 276, 482, 823, 1383, 2298, 3788, 6209, 10137, 16505, 26821, 43526, 70569, 114340, 185178, 299812, 485310, 785469, 1271154, 2057027, 3328615, 5386107, 8715219, 14101856, 22817639, 36920094, 59738368, 96659134
Offset: 0

Views

Author

Clark Kimberling, Nov 18 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.

Examples

			a(0) = 1, a(1) = 2, b(0) = 3
b(1) = 4 (least "new number")
a(2) = a(1) + a(0) + b(1) = Complement: (b(n)) = (3, 4, 5, 6, 8, 9, 10, 11, 12, 13, 14, ...)
		

Crossrefs

Cf. A295053.

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 1; a[1] = 2; b[0] = 3;
    a[n_] := a[n] = a[n - 1] + a[n - 2] + Sum[b[k], {k, 1, n - 1}];
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295054 *)
    Table[b[n], {n, 0, 10}]

A295055 Solution of the complementary equation a(n) = a(n-2) + b(0) + b(1) + ... + b(n-1), where a(0) = 1, a(1) = 2, b(0) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

1, 2, 8, 14, 26, 39, 60, 83, 115, 150, 195, 245, 306, 373, 452, 538, 637, 744, 865, 995, 1140, 1295, 1467, 1650, 1851, 2064, 2296, 2541, 2806, 3085, 3385, 3700, 4037, 4390, 4767, 5161, 5580, 6017, 6480, 6962, 7471, 8000, 8557, 9135, 9742, 10371, 11030, 11712
Offset: 0

Views

Author

Clark Kimberling, Nov 18 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.

Examples

			a(0) = 1, a(1) = 2, b(0) = 3
b(1) = 4 (least "new number")
a(2) = a(0) + b(0) + b(1) = 8
Complement: (b(n)) = (3, 4, 5, 6, 7, 9, 10, 11, 12, 13, 15, ...)
		

Crossrefs

Cf. A295053.

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 1; a[1] = 2; b[0] = 3;
    a[n_] := a[n] = a[n - 2] + Sum[b[k], {k, 0, n - 1}];
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295055 *)
    Table[b[n], {n, 0, 10}]

A295056 Solution of the complementary equation a(n) = 2*a(n-1) + b(n-1), where a(0) = 1, a(1) = 4, b(0) = 2, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

1, 4, 11, 27, 60, 127, 262, 533, 1076, 2164, 4341, 8696, 17407, 34830, 69677, 139372, 278763, 557546, 1115113, 2230248, 4460519, 8921062, 17842149, 35684324, 71368676, 142737381, 285474792, 570949615
Offset: 0

Views

Author

Clark Kimberling, Nov 18 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.

Examples

			a(0) = 1, a(1) = 4, b(0) = 2
b(1) = 3 (least "new number")
a(2) = 2*a(1) + b(1) = 11
Complement: (b(n)) = (2, 3, 5, 6, 7, 8, 9, 10, 12, 13, 14, ...)
		

Crossrefs

Cf. A295053.

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 1; a[1] = 4; b[0] = 2;
    a[n_] := a[n] = 2 a[n - 1] + b[n - 1];
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295056 *)
    Table[b[n], {n, 0, 10}]

A295057 Solution of the complementary equation a(n) = 2*a(n-1) + b(n-1), where a(0) = 2, a(1) = 5, b(0) = 1, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

2, 5, 13, 30, 66, 139, 286, 581, 1172, 2355, 4722, 9458, 18931, 37878, 75773, 151564, 303147, 606314, 1212649, 2425320, 4850663, 9701350, 19402725, 38805476, 77610979, 155221986, 310444001, 620888033
Offset: 0

Views

Author

Clark Kimberling, Nov 18 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.

Examples

			a(0) = 2, a(1) = 5, b(0) = 1
b(1) = 3 (least "new number")
a(2) = 2*a(1) + b(1) = 13
Complement: (b(n)) = (1, 3, 4, 6, 7, 8, 9, 10, 11, 12, 14, ...)
		

Crossrefs

Cf. A295053.

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 2; a[1] = 5; b[0] = 1;
    a[n_] := a[n] = 2 a[n - 1] + b[n - 1];
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295057 *)
    Table[b[n], {n, 0, 10}]

A295058 Solution of the complementary equation a(n) = 2*a(n-1) - b(n-1), where a(0) = 3, a(1) = 5, b(0) = 1, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

3, 5, 8, 12, 18, 29, 49, 88, 165, 317, 620, 1225, 2434, 4851, 9683, 19346, 38671, 77320, 154617, 309210, 618395, 1236764, 2473501, 4946974, 9893918, 19787805, 39575578, 79151123, 158302212, 316604389, 633208742
Offset: 0

Views

Author

Clark Kimberling, Nov 18 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.

Examples

			a(0) = 3, a(1) = 5, b(0) = 1
b(1) = 2 (least "new number")
a(2) = 2*a(1) - b(1) = 8
Complement: (b(n)) = (1, 2, 4, 6, 7, 9, 10, 11, 13, 14, 15, ...)
		

Crossrefs

Cf. A295053.

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 3; a[1] = 5; b[0] = 1;
    a[n_] := a[n] = 2 a[n - 1] - b[n - 1];
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295058 *)
    Table[b[n], {n, 0, 10}]

A295059 Solution of the complementary equation a(n) = 2*a(n-1) + b(n-2), where a(0) = 1, a(1) = 4, b(0) = 2, b(1) = 3, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

1, 4, 10, 23, 51, 108, 223, 454, 917, 1845, 3702, 7417, 14848, 29711, 59438, 118893, 237804, 475627, 951274, 1902569, 3805160, 7610344, 15220713, 30441452, 60882931, 121765890, 243531809, 487063648
Offset: 0

Views

Author

Clark Kimberling, Nov 18 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.

Examples

			a(0) = 1, a(1) = 4, b(0) = 2, b(1) = 3
a(2) = 2*a(1) + b(0) = 10
Complement: (b(n)) = (2, 3, 5, 6, 7, 8, 9, 11, 12, 13, 14, ...)
		

Crossrefs

Cf. A295053.

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 2; a[1] = 5; b[0] = 1;
    a[n_] := a[n] = 2 a[n - 1] + b[n - 1];
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295059 *)
    Table[b[n], {n, 0, 10}]

A295060 Solution of the complementary equation a(n) = 2*a(n-1) - b(n-2), where a(0) = 3, a(1) = 5, b(0) = 1, b(1) = 2, and (a(n)) and (b(n)) are increasing complementary sequences.

Original entry on oeis.org

3, 5, 9, 16, 28, 50, 93, 178, 346, 681, 1350, 2687, 5360, 10705, 21393, 42768, 85517, 171014, 342007, 683992, 1367961, 2735898, 5471771, 10943516, 21887005, 43773981, 87547932, 175095833, 350191634
Offset: 0

Views

Author

Clark Kimberling, Nov 18 2017

Keywords

Comments

The increasing complementary sequences a() and b() are uniquely determined by the titular equation and initial values. See A295053 for a guide to related sequences.

Examples

			a(0) = 1, a(1) = 4, b(0) = 2, b(1) = 3
a(2) = 2*a(1) - b(0) = 9
Complement: (b(n)) = (1, 2, 4, 6, 7, 8, 10, 11, 12, 13, 14, ...)
		

Crossrefs

Cf. A295053.

Programs

  • Mathematica
    mex := First[Complement[Range[1, Max[#1] + 1], #1]] &;
    a[0] = 3; a[1] = 5; b[0] = 1; b[1]=2;
    a[n_] := a[n] = 2 a[n - 1] - b[n - 2];
    b[n_] := b[n] = mex[Flatten[Table[Join[{a[n]}, {a[i], b[i]}], {i, 0, n - 1}]]];
    Table[a[n], {n, 0, 18}]  (* A295060 *)
    Table[b[n], {n, 0, 10}]
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