A104177 A variation on Flavius's sieve (A000960): Start with the natural numbers; at the k-th sieving step, remove every f-th term of the sequence remaining after the (k-1)-st sieving step, where f is the (k+2)-nd Fibonacci number, f=F(k+2); iterate.
1, 3, 7, 9, 15, 19, 21, 31, 33, 37, 39, 45, 51, 61, 63, 67, 69, 75, 79, 81, 93, 97, 99, 109, 111, 121, 123, 127, 129, 135, 139, 141, 151, 157, 165, 169, 171, 181, 183, 189, 195, 199, 201, 211, 213, 219, 225, 229, 231, 241, 243, 247, 249, 255, 261, 271, 277, 279
Offset: 1
Examples
Start with 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 ... (A000027) First sieving step: Delete every 2nd term (2=F(1+2)), giving 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 ... (A005408) 2nd sieving step: Delete every 3rd term (3=F(2+2)), giving 1 3 7 9 13 15 19 21 25 27 31 ... (A056530) 3rd sieving step: Delete every 5th (5=F(3+2)) term, giving 1 3 7 9 15 19 21 25 31 ... 4th sieving step: Delete every 8th (8=F(4+2)) term, giving 1 3 7 9 15 19 21 31 ... Continue forever and whatever remains is the sequence.
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