A006064 Smallest junction number with n generators.
0, 101, 10000000000001, 1000000000000000000000102
Offset: 1
Examples
a(2) = 101 since 101 is the smallest number with two generators: 101 = A062028(91) = A062028(100). a(4) = 10^24 + 102 = 1000000000000000000000102 has exactly four inverses w.r.t. A062028, namely 999999999999999999999893, 999999999999999999999902, 1000000000000000000000091 and 1000000000000000000000100.
References
- M. Gardner, Time Travel and Other Mathematical Bewilderments. Freeman, NY, 1988, p. 116.
- D. R. Kaprekar, The Mathematics of the New Self Numbers, Privately printed, 311 Devlali Camp, Devlali, India, 1963.
- Narasinga Rao, A. On a technique for obtaining numbers with a multiplicity of generators. Math. Student 34 1966 79--84 (1967). MR0229573 (37 #5147)
- N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
Links
- Max Alekseyev, Table of expressions for a(n), for n=1..100
- Max A. Alekseyev and N. J. A. Sloane, On Kaprekar's Junction Numbers, arXiv:2112.14365, 2021; Journal of Combinatorics and Number Theory 12:3 (2022), 115-155.
- Shyam Sunder Gupta, On Some Marvellous Numbers of Kaprekar, Exploring the Beauty of Fascinating Numbers, Springer (2025) Ch. 9, 275-315.
- D. R. Kaprekar, The Mathematics of the New Self Numbers [annotated and scanned]
- N. J. A. Sloane, "A Handbook of Integer Sequences" Fifty Years Later, arXiv:2301.03149 [math.NT], 2023, p. 21.
- Terry Trotter, Charlene numbers
- Index entries for Colombian or self numbers and related sequences
Crossrefs
Formula
a(n) = the smallest m such that there are exactly n solutions to A062028(x)=m.
Extensions
Edited, a(5)-a(6) added by Max Alekseyev, Jun 01 2011
a(1) added, a(5) corrected, a(7)-a(8) added by Max Alekseyev, Oct 26 2013
Comments