A011117 Triangle of numbers S(x,y) = number of lattice paths from (0,0) to (x,y) that use step set { (0,1), (1,0), (2,0), (3,0), ....} and never pass below y = x.
1, 1, 1, 1, 2, 3, 1, 3, 7, 11, 1, 4, 12, 28, 45, 1, 5, 18, 52, 121, 197, 1, 6, 25, 84, 237, 550, 903, 1, 7, 33, 125, 403, 1119, 2591, 4279, 1, 8, 42, 176, 630, 1976, 5424, 12536, 20793, 1, 9, 52, 238, 930, 3206, 9860, 26832, 61921, 103049, 1, 10, 63
Offset: 0
Examples
Triangle starts: [0] [1] [1] [1, 1] [2] [1, 2, 3] [3] [1, 3, 7, 11] [4] [1, 4, 12, 28, 45] [5] [1, 5, 18, 52, 121, 197] [6] [1, 6, 25, 84, 237, 550, 903] [7] [1, 7, 33, 125, 403, 1119, 2591, 4279] [8] [1, 8, 42, 176, 630, 1976, 5424, 12536, 20793] [9] [1, 9, 52, 238, 930, 3206, 9860, 26832, 61921, 103049]
Links
- E. Barcucci, E. Pergola, R. Pinzani and S. Rinaldi, ECO method and hill-free generalized Motzkin paths, Séminaire Lotharingien de Combinatoire, B46b (2001), 14 pp.
- E. Pergola and R. A. Sulanke, Schroeder Triangles, Paths and Parallelogram Polyominoes, J. Integer Sequences, 1 (1998), #98.1.7.
Crossrefs
Programs
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Mathematica
f[ x_, y_ ] := f[ x, y ] = Module[ {return}, If[ x == 0, return = 1, If[ y == x-1, return = 0, return = f[ x, y-1 ] + Sum[ f[ k, y ], {k, 0, x-1} ] ] ]; return ]; Do[ Print[ Table[ f[ k, j ], {k, 0, j} ] ], {j, 10, 0, -1} ]
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Sage
def A011117_row(n): @cached_function def prec(n, k): if k==n: return 1 if k==0: return 0 return prec(n-1,k-1)+sum(prec(n,k+i-1) for i in (2..n-k+1)) return [prec(n, n-k) for k in (0..n-1)] for n in (1..9): print(A011117_row(n)) # Peter Luschny, Mar 16 2016
Formula
S(m, n) = ((n-m+1)/(n+1))*Sum_{i=0..m-1} 2^(m-i-1)*binomial(n+1, i+1)*binomial(m-1, i).
Another version of triangle [1, 0, 0, 0, 0, 0, ...] DELTA [0, 1, 2, 1, 2, 1, 2, 1, 2, 1, ...] = 1, 1, 0, 1, 1, 0, 1, 2, 3, 0, 1, 3, 7, 11, 0, 1, 4, 12, 28, 45, 0, 1, ..., where DELTA is Deléham's operator defined in A084938.
G.f.: 2/(1 + uv - 2v + sqrt(1 - 6uv + u^2v^2)). - Emeric Deutsch, Dec 25 2003
Sum_{k = 0..n} T(n, k) = A006318(n), large Schroeder numbers. - Philippe Deléham, Jul 10 2004. (This is because T(n, k) = number of royal paths (A006318) of length n with exactly n-k Northeast steps lying on the line y=x. - David Callan, Aug 02 2004)
S(n,m) = ((n-m+1)/m)*Sum_{k=1..m} binomial(m,k)*binomial(n+k,k-1), n >= m > 1; S(n,0)=1; S(n,m)=0, n < m. See the corresponding formula for A104219. - Wolfdieter Lang, Mar 16 2009
Comments