A026921 Triangular array E by rows: E(n,k) = number of partitions of n into an even number of parts, the greatest being k.
0, 1, 0, 0, 1, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 2, 1, 1, 0, 0, 2, 1, 2, 1, 1, 0, 1, 2, 3, 2, 2, 1, 1, 0, 0, 2, 3, 3, 2, 2, 1, 1, 0, 1, 2, 5, 4, 4, 2, 2, 1, 1, 0, 0, 3, 4, 6, 4, 4, 2, 2, 1, 1, 0, 1, 3, 7, 7, 7, 5, 4, 2, 2, 1, 1, 0, 0, 3, 6, 10, 8, 7, 5, 4, 2, 2, 1, 1, 0, 1, 3, 9, 11, 13, 9, 8, 5, 4, 2, 2, 1, 1, 0
Offset: 1
Examples
G.f. = (1)*q^0 + (0) * q^1 + (1 + 0*z) * q^2 + (0 + 1*z + 0*z^2) * q^3 + (1 + 1*z + 1*z^2 + 0*z^3) * q^4 + (0 + 1*z + 1*z^2 + 1*z^3 + 0*z^4) * q^5 + (1 + 1*z + 2*z^2 + 1*z^3 + 1*z^4 + 0*z^5) * q^6 + (0 + 2*z + 1*z^2 + 2*z^3 + 1*z^4 + 1*z^5 + 0*z^6) * q^7 + ... [_Joerg Arndt_, May 12 2013] Triangle starts: 01: [0] 02: [1, 0] 03: [0, 1, 0] 04: [1, 1, 1, 0] 05: [0, 1, 1, 1, 0] 06: [1, 1, 2, 1, 1, 0] 07: [0, 2, 1, 2, 1, 1, 0] 08: [1, 2, 3, 2, 2, 1, 1, 0] 09: [0, 2, 3, 3, 2, 2, 1, 1, 0] 10: [1, 2, 5, 4, 4, 2, 2, 1, 1, 0] 11: [0, 3, 4, 6, 4, 4, 2, 2, 1, 1, 0] 12: [1, 3, 7, 7, 7, 5, 4, 2, 2, 1, 1, 0] 13: [0, 3, 6, 10, 8, 7, 5, 4, 2, 2, 1, 1, 0] 14: [1, 3, 9, 11, 13, 9, 8, 5, 4, 2, 2, 1, 1, 0] 15: [0, 4, 8, 14, 14, 14, 9, 8, 5, 4, 2, 2, 1, 1, 0] 16: [1, 4, 12, 16, 20, 17, 15, 10, 8, 5, 4, 2, 2, 1, 1, 0] 17: [0, 4, 11, 20, 22, 23, 18, 15, 10, 8, 5, 4, 2, 2, 1, 1, 0] 18: [1, 4, 15, 23, 30, 28, 26, 19, 16, 10, 8, 5, 4, 2, 2, 1, 1, 0] 19: [0, 5, 13, 28, 33, 37, 31, 27, 19, 16, 10, 8, 5, 4, 2, 2, 1, 1, 0] 20: [1, 5, 18, 31, 44, 44, 43, 34, 28, 20, 16, 10, 8, 5, 4, 2, 2, 1, 1, 0] ... [_Joerg Arndt_, May 12 2013]
Crossrefs
Programs
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PARI
N = 20; q = 'q + O('q^N); gf = sum(n=0,N, q^(2*n)/prod(k=1, 2*n, 1-'z*q^k) ); v = Vec(gf); { for(n=2, #v, /* print triangle starting with row 1: */ p = Pol('c0 +'cn*'z^n + v[n],'z); p = polrecip(p); p = Vec(p); p[1] -= 'c0; p = vector(#p-2, j, p[j]); print(p); ); } /* Joerg Arndt, May 12 2013 */
Formula
G.f. (including term a(0)=1): sum(n>=0, q^(2*n)/prod(k=1..2*n, 1-z*q^k) ), set z=1 to obtain g.f. for A027187. [Joerg Arndt, May 12 2013]
Comments