A036106 A summarize Fibonacci sequence: summarize the previous two terms!.
1, 2, 1211, 2231, 133241, 14333231, 24632241, 1634534231, 261544434231, 262564533241, 363564435231, 464544634221, 463574533221, 17363574434221, 37263554634231, 37363554734231, 37364544933221, 1937263554933221
Offset: 0
Examples
a(24) = 293847463554538221; a(25) = 294827365564537221 = first term of first period; a(26) = 293837366554537221; a(70) = 294837364554538221 = last term of first period != a(24); a(71) = 294827365564537221 = a(25) = first term of second period; a(72) = 293837366554537221 = a(26); a(116) = 294837364554538221 = a(70) = last term of second period; a(117) = 294827365564537221 = a(71) = first term of third period.
Links
- Reinhard Zumkeller, Table of n, a(n) for n = 0..254 = 5 periods.
- Index to sequences related to say what you see
Crossrefs
Cf. A036059.
Programs
-
Haskell
import Data.List (sort, group); import Data.Function (on) a036106 n = a036106_list !! n a036106_list = 1 : 2 : map (read . concatMap say . reverse . group . sort) (zipWith ((++) `on` show) a036106_list $ tail a036106_list) where say ws = (show $ length ws) ++ [head ws] -- Reinhard Zumkeller, Oct 05 2015
-
Mathematica
a[0] = 1; a[1] = 2; a[n_] := a[n] = Reverse /@ (IntegerDigits /@ {a[n-2], a[n-1]} // Flatten // Tally // Sort // Reverse) // Flatten // FromDigits; Table[a[n], {n, 0, 17}] (* Jean-François Alcover, Nov 02 2016 *)
Comments