cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A114687 Triangle read by rows: T(n,k) is the number of double rise-bicolored Dyck paths (double rises come in two colors; also called marked Dyck paths) of semilength n and having k double rises (0 <= k <= n-1).

Original entry on oeis.org

1, 1, 2, 1, 6, 4, 1, 12, 24, 8, 1, 20, 80, 80, 16, 1, 30, 200, 400, 240, 32, 1, 42, 420, 1400, 1680, 672, 64, 1, 56, 784, 3920, 7840, 6272, 1792, 128, 1, 72, 1344, 9408, 28224, 37632, 21504, 4608, 256, 1, 90, 2160, 20160, 84672, 169344, 161280, 69120, 11520
Offset: 1

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Author

Emeric Deutsch, Dec 23 2005

Keywords

Comments

Row sums are the little Schroeder numbers (A001003). Sum(k*T(n,k),k=0..n-1) = 2*A050152(n-1). Mirror image of A114656.
Triangle T(n,k) given (essentially) by [1,0,1,0,1,0,1,0,1,0,1,0,...] DELTA [0,2,0,2,0,2,0,2,0,2,0,...] where DELTA is the operator defined in A084938. - Philippe Deléham, Jan 02 2009
T(r, m) is the number distinct extremities of the [0,r]-covering hierarchies with segments terminating at r (see Kreweras work). - Michel Marcus, Nov 22 2014

Examples

			T(3,2)=4 because we have UbUbUDDD, UbUrUDDD, UrUbUDDD and UrUrUDDD, where U=(1,1), D=(1,-1) and b (r) indicates a blue (red) double rise.
Triangle begins:
  1;
  1,  2;
  1,  6,  4;
  1, 12, 24,  8;
  1, 20, 80, 80, 16.
Triangle [1,0,1,0,1,0,1,0,...] DELTA [0,2,0,2,0,2,0,2,0,...]:= T(n,k), 0 <= k <= n, begins: 1; 1,0; 1,2,0; 1,6,4,0; 1,12,24,8,0; 1,20,80,80,16,0; ... - _Philippe Deléham_, Jan 02 2009
		

Crossrefs

Programs

  • Maple
    T:=(n,k)->2^k*binomial(n,k)*binomial(n,k+1)/n: for n from 1 to 11 do seq(T(n,k),k=0..n-1) od;
  • Mathematica
    Table[2^k*Binomial[n, k] Binomial[n, k + 1]/n, {n, 10}, {k, 0, n - 1}] // Flatten (* Michael De Vlieger, Nov 05 2017 *)
  • PARI
    t(r, m) = 2^m*binomial(r, m)*binomial(r, m+1)/r;
    tabl(nn) = {for (n=1, nn, for (k=0, n-1, print1(t(n,k), ", ");); print(););} \\ Michel Marcus, Nov 22 2014

Formula

T(n, k) = 2^k * binomial(n, k) * binomial(n, k+1)/n.
G.f.: G=G(t, z) satisfies G = z*(1+G)*(1+2*t*G).
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