cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A179611 Eight white kings and one red king on a 3 X 3 chessboard. G.f.: (1+2*x)/(1 - 2*x - 8*x^2 - 4*x^3).

Original entry on oeis.org

1, 4, 16, 68, 280, 1168, 4848, 20160, 83776, 348224, 1447296, 6015488, 25002240, 103917568, 431915008, 1795179520, 7461349376, 31011794944, 128895102976, 535729963008, 2226667929600, 9254755975168, 38465775239168
Offset: 0

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Author

Johannes W. Meijer, Jul 28 2010

Keywords

Comments

The a(n) represent the number of n-move routes of a fairy chess piece starting in the central square (m = 5) on a 3 X 3 chessboard. This fairy chess piece behaves like a king on the eight side and corner squares but on the central square the king goes crazy and turns into a red king, see A179596.
The sequence above corresponds to 36 red king vectors, i.e., A[5] vectors, with decimal values 15, 39, 45, 75, 78, 99, 102, 105, 108, 135, 141, 165, 195, 198, 201, 204, 225, 228, 267, 270, 291, 294, 297, 300, 330, 354, 360, 387, 390, 393, 396, 417, 420, 450, 456 and 480.

Crossrefs

Cf. A179596, A179597 (central square).
Cf. A052904.

Programs

  • Maple
    with(LinearAlgebra): nmax:=22; m:=5; A[1]:= [0,1,0,1,1,0,0,0,0]: A[2]:= [1,0,1,1,1,1,0,0,0]: A[3]:= [0,1,0,0,1,1,0,0,0]: A[4]:=[1,1,0,0,1,0,1,1,0]: A[5]:= [0,0,0,0,0,1,1,1,1]: A[6]:= [0,1,1,0,1,0,0,1,1]: A[7]:= [0,0,0,1,1,0,0,1,0]: A[8]:= [0,0,0,1,1,1,1,0,1]: A[9]:= [0,0,0,0,1,1,0,1,0]: A:=Matrix([A[1],A[2],A[3],A[4],A[5],A[6],A[7],A[8],A[9]]): for n from 0 to nmax do B(n):=A^n: a(n):= add(B(n)[m,k],k=1..9): od: seq(a(n), n=0..nmax);
  • Mathematica
    LinearRecurrence[{2,8,4},{1,4,16},30] (* Harvey P. Dale, Oct 20 2017 *)

Formula

G.f.: (1+2*x)/(1 - 2*x - 8*x^2 - 4*x^3).
a(n) = 2*a(n-1) + 8*a(n-2) + 4*a(n-3) with a(1)=1, a(2)=4 and a(3)=16.
a(n) = (8 + 3*z1 - 6*z1^2)*z1^(-n)/(z1*37) + (8 + 3*z2 - 6*z2^2)*z2^(-n)/(z2*37) + (8 + 3*z3 - 6*z3^2)*z3^(-n)/(z3*37) with z1, z2 and z3 the roots of f(x) = 1 - 2*x - 8*x^2 - 4*x^3 = 0.
alpha = arctan(3*sqrt(111));
z1 = sqrt(10)*cos(alpha/3)/6 + sqrt(30)*sin(alpha/3)/6 - 2/3 = 0.2405971520460078;
z2 = -sqrt(10)*cos(alpha/3)/3 - 2/3 = -1.585043243313016;
z3 = sqrt(10)*cos(alpha/3)/6 - sqrt(30)*sin(alpha/3)/6 - 2/3 = -0.6555539087329909.
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