A056131 Sequence A001033 gives the numbers n such that the sum of the squares of n consecutive odd numbers x^2 + (x+2)^2 + ... +(x+2n-2)^2 = k^2 for some integer k. For each n, this sequence gives the least value of x.

1, 27, 27, 91, 151, 225, 31, 67, 14037, 47, 119, 4177, 165, 103, 3599, 291, 11467887, 3089, 1297, 379, 57, 131, 110311, 153, 2637, 353, 163, 1679, 1211, 995, 54863, 105, 43, 615, 439, 15, 12955, 2263, 11661, 1867, 1281, 1433, 46671, 303, 21139, 324545, 4159, 343803

Offset: 1

Author

Robert G. Wilson v, Aug 04 2000

Keywords

• nonn

Examples

			995 is a term because the sum of the squares of 400 consecutive odd numbers beginning with 995 is 28260^2.
		

Links

• Christopher E. Thompson, Table of n, a(n) for n = 1..7103 (extends first 100 terms computed by T. D. Noe).

Crossrefs

Cf. A001033, A056132.

Extensions

Corrected and extended by T. D. Noe, Oct 24 2007

Term corresponding to 1024 in A001033 was missing from b-file. Christopher E. Thompson, Feb 05 2016