A056508 Number of periodic palindromic structures of length n using exactly two different symbols.
0, 1, 1, 3, 3, 6, 7, 13, 15, 25, 31, 50, 63, 99, 127, 197, 255, 391, 511, 777, 1023, 1551, 2047, 3090, 4095, 6175, 8191, 12323, 16383, 24639, 32767, 49221, 65535, 98431, 131071, 196743, 262143, 393471, 524287, 786697, 1048575, 1573375, 2097151, 3146255, 4194303
Offset: 1
Keywords
Examples
From _Andrew Howroyd_, Apr 07 2017: (Start) Example for n=6: Periodic symmetry means results are either in the form abccba or abcdcb. There are 3 binary words in the form abccba that start with 0 and contain a 1 which are 001100, 010010, 011110. Of these, 011110 is equivalent to 001100 after rotation. There are 7 binary words in the form abcdcb that start with 0 and contain a 1 which are 000100, 001010, 001110, 010001, 010101, 011011, 011111. Of these, 011111 is equivalent to 000100, 010001 is equivalent to 001010 and 011011 is equivalent to 010010 from the first set. There are therefore a total of 7 + 3 - 4 = 6 equivalence classes so a(6) = 6. (End)
References
- M. R. Nester (1999). Mathematical investigations of some plant interaction designs. PhD Thesis. University of Queensland, Brisbane, Australia. [See A056391 for pdf file of Chap. 2]
Links
- Giovanni Resta, Table of n, a(n) for n = 1..1000
Programs
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Mathematica
(* b = A164090, c = A045674 *) b[n_] := (1/4)*(7 - (-1)^n)*2^((1/4)*(2*n + (-1)^n - 1)); c[0] = 1; c[n_] := c[n] = If[EvenQ[n], 2^(n/2 - 1) + c[n/2], 2^((n - 1)/2)]; a[n_] := If[OddQ[n], b[n]/2, (1/2)*(b[n] + c[n/2])] - 1; Array[a, 45] (* Jean-François Alcover, Jun 29 2018, after Andrew Howroyd *)
Formula
a(n) = A056503(n) - 1.
a(2n + 1) = 2^n - 1. - Andrew Howroyd, Apr 07 2017
Extensions
a(17)-a(45) from Andrew Howroyd, Apr 07 2017
Comments