A059572 From Mertens's conjecture (2): floor(sqrt(n)) - Mertens's function A002321(n).
0, 1, 2, 3, 4, 3, 4, 4, 5, 4, 5, 5, 6, 5, 4, 5, 6, 6, 7, 7, 6, 5, 6, 6, 7, 6, 6, 6, 7, 8, 9, 9, 8, 7, 6, 7, 8, 7, 6, 6, 7, 8, 9, 9, 9, 8, 9, 9, 10, 10, 9, 9, 10, 10, 9, 9, 8, 7, 8, 8, 9, 8, 8, 9, 8, 9, 10, 10, 9, 10, 11, 11, 12, 11, 11, 11, 10, 11, 12, 12, 13, 12, 13
Offset: 1
Keywords
References
- D. S. Mitrinovic et al., Handbook of Number Theory, Kluwer, Section VI.2.
Links
- Paolo Xausa, Table of n, a(n) for n = 1..10000
- A. M. Odlyzko and H. J. J. te Riele, Disproof of the Mertens conjecture, J. reine angew. Math., 357 (1985), pp. 138-160.
Programs
-
Mathematica
Table[Floor[Sqrt[n]] - Plus @@ MoebiusMu[Range[n]], {n, 1, 80}] (* Carl Najafi, Aug 17 2011 *)
Comments