cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A344427 Decimal expansion of -zeta'(alpha), where alpha = A069995 is the fixed point of Riemann zeta function in (1, +oo).

Original entry on oeis.org

1, 3, 7, 4, 2, 5, 2, 4, 3, 0, 2, 4, 7, 1, 8, 9, 9, 0, 6, 1, 8, 3, 7, 2, 7, 5, 8, 6, 1, 3, 7, 8, 2, 8, 6, 0, 0, 1, 6, 3, 7, 8, 9, 6, 6, 1, 6, 0, 2, 3, 4, 0, 1, 6, 4, 5, 7, 8, 3, 9, 8, 9, 9, 8, 5, 6, 1, 9, 1, 3, 0, 0, 6, 9, 7, 5, 1, 4, 2, 6, 3, 3, 4, 9, 8, 3, 2, 6, 8, 6
Offset: 1

Views

Author

Jianing Song, May 19 2021

Keywords

Comments

|zeta'(alpha)| > 1 means that s = alpha is a repelling fixed point of zeta(s). As a result, for any initial value s_0 in (1, +oo), s_0 != alpha, the iterated sequence s_0, zeta(s_0), zeta(zeta(s_0)), ... diverges.
Moreover, let s_0 be any real number > alpha, s_n = zeta(s_{n-1}) for n >= 1, then it seems that ... > s_{2n} > s_{2n-2} > ... > s_2 > s_0 > alpha > s_1 > s_3 > ... > s_{2n+1} > ..., and {s_{2n}} diverges to +oo, {s_{2n+1}} converges to 1. Moreover, the divergence of {s_{2n}} and convergence of {s_{2n+1}} should be really fast, see my conjecture in A344428.

Examples

			zeta'(1.83377265168027139624...) = -1.37425243024718990618...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[-Zeta'[x /. FindRoot[Zeta[x] == x, {x, 2}, WorkingPrecision -> 120]]][[1]] (* Amiram Eldar, Jun 01 2023 *)
  • PARI
    default(realprecision, 100); zeta'(solve(x=1.5, 2, zeta(x)-x))

A324859 Decimal expansion of 0.1990753..., an inflection point of a Hurwitz zeta fixed-point function.

Original entry on oeis.org

1, 9, 9, 0, 7, 5, 3, 0, 3, 5, 4, 4, 7, 7, 2, 8, 5, 4, 9, 7, 1, 1, 3, 0, 0, 3, 5, 0, 7, 2, 2, 2, 8, 4, 2, 1, 6, 8, 8, 2, 8, 6, 6, 3, 2, 0, 1, 6, 3, 1, 5, 1, 0, 7, 6, 1, 0, 1, 4, 8, 1, 0, 1, 7, 7, 9, 7, 0, 6, 9, 3, 8, 2, 0, 3, 4, 0, 7, 2, 1, 0, 3, 6, 6, 9, 8, 1, 6, 4, 0, 4, 4, 7, 4, 9, 2, 4, 1, 9, 7
Offset: 0

Views

Author

Reikku Kulon, Mar 18 2019

Keywords

Comments

For real values of the parameter "a" between 0 and 1, a real fixed point "s" of the iterated Hurwitz zeta function [s = zetahurwitz(s, a)] lies on a curve that passes through A069857 (-0.295905...) and has a maximum tending toward 1. This curve has inflection points for a = 0.1990753... or 0.91964... . The fixed point "s" on this curve for the iteration "s = zetahurwitz(s, A324859)" is A324860 (0.5250984...).

Examples

			0.1990753035447728549711300350722284216882866320163...
		

Crossrefs

Programs

  • PARI
    solve(t = 1/16, 1/2, derivnum(x = t, solve(v = -1, 1 - x, v - zetahurwitz(v, x)), 2); )

A324860 Decimal expansion of 0.5250984..., a real fixed point of the iteration s = zetahurwitz(s, A324859).

Original entry on oeis.org

5, 2, 5, 0, 9, 8, 4, 2, 4, 6, 2, 8, 8, 9, 2, 5, 7, 2, 1, 1, 5, 4, 3, 8, 9, 1, 2, 3, 9, 5, 8, 5, 1, 3, 1, 6, 4, 2, 9, 6, 3, 1, 1, 0, 7, 5, 4, 8, 7, 9, 6, 3, 2, 0, 1, 8, 8, 7, 0, 2, 4, 4, 4, 9, 1, 7, 8, 5, 4, 5, 6, 9, 1, 4, 0, 6, 5, 5, 2, 5, 1, 2, 7, 7, 0, 0, 7, 6, 0, 9, 1, 1, 9, 5, 2, 7, 2, 0, 9, 5
Offset: 0

Views

Author

Reikku Kulon, Mar 18 2019

Keywords

Comments

For real values of the parameter "a" between 0 and 1, a real fixed point "s" of the iterated Hurwitz zeta function [s = zetahurwitz(s, a)] lies on a curve that passes through A069857 (-0.295905...) and has a maximum tending toward 1. This curve has inflection points for a = 0.1990753... (A324859) or 0.91964... . The fixed point "s" on this curve for the iteration "s = zetahurwitz(s, A324859)" is 0.5250984... .

Examples

			0.525098424628892572115438912395851316429631107548...
		

Crossrefs

Programs

  • PARI
    { A324859 = solve(t = 1/16, 1/2, derivnum(x = t, solve(v = -1, 1 - x, v - zetahurwitz(v, x)), 2); ); solve(v = -1, 1 - A324859, v - zetahurwitz(v, A324859)) }

A344428 Decimal expansion of exp(-2/5).

Original entry on oeis.org

6, 7, 0, 3, 2, 0, 0, 4, 6, 0, 3, 5, 6, 3, 9, 3, 0, 0, 7, 4, 4, 4, 3, 2, 9, 2, 5, 1, 4, 7, 8, 2, 6, 0, 7, 1, 9, 3, 6, 9, 8, 0, 9, 2, 5, 2, 1, 0, 8, 1, 2, 1, 9, 9, 8, 8, 8, 9, 1, 0, 3, 3, 1, 6, 2, 5, 8, 9, 4, 1, 7, 5, 1, 2, 0, 3, 5, 3, 7, 4, 3, 8, 2, 6, 3, 3, 7, 5, 4, 3, 9
Offset: 0

Views

Author

Jianing Song, May 19 2021

Keywords

Comments

Let f(s) = zeta(zeta(s+1)) - 1, where zeta(s) is the Riemann zeta function. Then f(s) is a strictly increasing function from (0, +oo) to (0, +oo), lim_{s->0+} f(s) = 0, lim_{s->+oo} f(s) = +oo.
Conjecture:
(i) f(s) has a unique fixed point s = A069995 - 1 in (0, +oo);
(ii) Lim_{s->+oo} f(s)/2^s = 1, lim_{s->0+} f(s)/2^(-1/s) = exp(-2/5) = A344428.
If these are true, let s_0 be any real number > alpha, s_n = zeta(s_{n-1}) for n >= 1, where alpha = A069995 is the fixed point of zeta(s) in (1, +oo), then {s_{2n}} diverges quickly to +oo, {s_{2n+1}} converges quickly to 1.
This is because the derivative of zeta(zeta(s)) - s at s = alpha is (zeta'(alpha))^2 - 1 = A344427^2 - 1 > 0, so (i) implies that zeta(zeta(s)) > s for s > alpha and zeta(zeta(s)) < s for 1 < s < alpha, hence ... > s_{2n} > s_{2n-2} > ... > s_2 > s_0 > alpha > s_1 > s_3 > ... > s_{2n+1} > ..., and it follows from (i) that lim_{n->+oo} s_{2n} = +oo, lim_{n->+oo} s_{2n+1} = 1. By definition s_n - 1 = f(s_{n-2} - 1), n >= 2. For large n, s_{2n} - 1 is approximately equal to 2^(s_{2(n-1)} - 1), and 1/(s_{2n+1} - 1) is approximately equal to exp(2/5) * 2^(1/(s_{2(n-1)+1} - 1)).

Examples

			exp(-2/5) = 0.67032004603563930074... In comparison, (zeta(zeta(0.001+1)) - 1) / 2^(-1/0.001) = 0.67022226725425164463...
		

Crossrefs

Programs

  • Mathematica
    RealDigits[Exp[-2/5], 10, 100][[1]] (* Amiram Eldar, May 19 2021 *)
  • PARI
    default(realprecision, 100); exp(-2/5)

A307065 Decimal expansion of the negative real attracting fixed point of Э(s) = (1 - 2^s) * (1 - 2^(1 - s)) * gamma(s) * zeta(s) * beta(s) / Pi^s.

Original entry on oeis.org

1, 7, 8, 4, 8, 3, 0, 9, 7, 1, 4, 2, 9, 5, 4, 5, 7, 0, 2, 8, 6, 0, 5, 7, 5, 4, 6, 6, 4, 2, 0, 3, 7, 0, 7, 6, 9, 9, 7, 8, 3, 1, 5, 9, 1, 5, 5, 9, 5, 0, 7, 2, 6, 1, 0, 4, 4, 7, 8, 5, 7, 2, 1, 3, 8, 6, 4, 9, 3, 3, 1, 7, 9, 2, 4, 1, 3, 6, 1, 7, 4, 9, 5, 3, 4, 0, 3, 7, 1, 7, 8, 9, 9, 8, 8, 7, 1, 2, 1, 7
Offset: 0

Views

Author

Reikku Kulon, Mar 22 2019

Keywords

Comments

Ossicini's function Э(s) is constructed to remove the poles of gamma(s) and zeta(s) along with the trivial zeros of zeta(s) and (Dirichlet) beta(s). Its zeros include the nontrivial zeros of zeta(s) and beta(s), and complex zeros contributed by (1 - 2^s) and (1 - 2^(1 - s)) at regular intervals of 2*Pi/log(2) on the lines Re(s) = {0, 1}.

Examples

			-0.1784830971429545702860575466420370769978315915595...
		

References

  • A. Ossicini, An alternative form of the functional equation for Riemann's Zeta function, Atti Semin. Mat. Fis. Univ. Modena Reggio Emilia 56 (2008/09), 95-111.

Crossrefs

Programs

  • Mathematica
    f[s_] := s - (1 - 2^s)(1 - 2^(1-s)) Gamma[s] Zeta[s] ((HurwitzZeta[s, 1/4] - HurwitzZeta[s, 3/4])/(4 Pi)^s);
    s0 = s /. FindRoot[f[s], {s, -1/5}, WorkingPrecision -> 100];
    RealDigits[s0][[1]] (* Jean-François Alcover, May 07 2019 *)
  • PARI
    solve(s = -1/2, -1/8, s - (1 - 2^s) * (1 - 2^(1 - s)) * gamma(s) * zeta(s) * (zetahurwitz(s, 1/4) - zetahurwitz(s, 3/4)) / (4 * Pi)^s)
Showing 1-5 of 5 results.