A072860 Highest power of 3 dividing the period length of 1/prime(n) = A002371(n).
0, 1, 0, 3, 1, 3, 1, 9, 1, 1, 3, 3, 1, 3, 1, 1, 1, 3, 3, 1, 1, 1, 1, 1, 3, 1, 1, 1, 27, 1, 3, 1, 1, 1, 1, 3, 3, 81, 1, 1, 1, 9, 1, 3, 1, 9, 3, 3, 1, 3, 1, 1, 3, 1, 1, 1, 1, 1, 3, 1, 3, 1, 9, 1, 3, 1, 1, 3, 1, 1, 1, 1, 3, 3, 27, 1, 1, 9, 1, 3, 1, 1, 1, 27, 3, 1, 1, 1, 1, 1, 1, 1, 243, 1, 3, 1, 1, 1, 9, 27
Offset: 1
Crossrefs
Cf. A002371.
Programs
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PARI
for n>3 ? a(n)=if(n<4,n==2,znorder(Mod(10, prime(n)))) ? for(n=4,150,print1(gcd(a(n),3^100),","))