A073088 Sum of first n terms of the simple continued fraction of Sum_{k>=0} 1/2^(2^k) (cf. A007400).

0, 1, 5, 7, 11, 15, 21, 25, 27, 31, 37, 39, 43, 49, 53, 57, 59, 63, 69, 71, 75, 79, 85, 89, 91, 97, 101, 103, 107, 113, 117, 121, 123, 127, 133, 135, 139, 143, 149, 153, 155, 159, 165, 167, 171, 177, 181, 185, 187, 193, 197, 199, 203, 207, 213, 217, 219, 225, 229

Offset: 1

Author

Benoit Cloitre, Aug 18 2002

Keywords

• easy
• nonn

Examples

			The first 9 terms are 0, 1, 4, 2, 4, 4, 6, 4, 2, hence a(9)= 0 + 1 + 4 + 2 + 4 + 4 + 6 + 4 + 2 = 27.
		

Crossrefs

Cf. A007400.

Formula

a(n) ~ 4n and a(n) < 4n.