A073096 Maximal element in continued fraction for s(n) = sum( k>=n,1/2^(2^k) ).

6, 6, 18, 258, 65538, 4294967298, 18446744073709551618, 340282366920938463463374607431768211458, 115792089237316195423570985008687907853269984665640564039457584007913129639938

Offset: 0

Author

Benoit Cloitre, Aug 18 2002

Keywords

• nonn

Examples

			Continued fraction expansion of 1/2^(2^5)+1/2^(2^6)+1/2^(2^7)+...is [0, 4294967295, 4294967298, 4294967296, 4294967296,... ] where the maximum element is 4294967298, hence a(5)=4294967298
		

Crossrefs

Cf. A007400 for case n=0.

Formula

a(0)=6; for n>0 a(n)=2^(2^n)+2.

a(n) = A063486(n)-3 for n>0. - R. J. Mathar, Apr 22 2007