A076213 2*a(n)-1 = sign(A005132(n+1)-A005132(n)).
1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 0
Offset: 0
Keywords
Formula
Conjecture: let s(n)=sum(k=1, n, a(k)), then lim n ->infinity s(n)/n = 1/2; for any n, 2*s(n) > n; let v(n)=2*s(n)-n, then v(n)/log(n) is bounded and sum(k=1, n, v(k)) is asymptotic to c*n*log(n) with 1 < c < 3/2.
Extensions
Added initial value a(0)=1. - M. F. Hasler, Jun 03 2009
Comments