A076535 a(n) = A064405 (2^m+n) - 2^m (for m large enough this difference appears to be constant).

-3, -6, -5, -12, -3, -10, -9, -24, 1, -6, -5, -20, -3, -18, -17, -48, 9, 2, 3, -12, 5, -10, -9, -40, 9, -6, -5, -36, -3, -34, -33, -96, 25, 18, 19, 4, 21, 6, 7, -24, 25, 10, 11, -20, 13, -18, -17, -80, 33, 18, 19, -12, 21, -10, -9, -72, 25, -6, -5, -68, -3, -66, -65, -192, 57, 50, 51, 36, 53, 38, 39, 8, 57, 42, 43, 12, 45, 14, 15

Offset: 0

Author

Benoit Cloitre, Oct 18 2002

Keywords

• sign

Examples

			For n=17; for m=1,2,3,4,5,6,7,8,9,10 values of A064405 (2^m+17) - 2^m are .... 2,2,2,10,2,2,2,2,2,2, so for n>4 the difference seems always equal to 2, hence a(17)=2
		

Crossrefs

Cf. A064405.

Programs

PARI

A001316(n)=sum(k=0,n,binomial(n,k)%2)
for(n=0,100,print1(n+1-4*A001316(n),",")) \\ Lambert Klasen

Formula

a(n) = n + 1 - 4*A001316(n). a(0) = -3, a(2n) = a(n) + n, a(2n+1) = 2a(n). - Ralf Stephan, Oct 08 2003

Extensions

More terms from Lambert Klasen (lambert.klasen(AT)gmx.de), Jan 14 2005