A076649 Number of digits required to write the prime factors of n.
0, 1, 1, 2, 1, 2, 1, 3, 2, 2, 2, 3, 2, 2, 2, 4, 2, 3, 2, 3, 2, 3, 2, 4, 2, 3, 3, 3, 2, 3, 2, 5, 3, 3, 2, 4, 2, 3, 3, 4, 2, 3, 2, 4, 3, 3, 2, 5, 2, 3, 3, 4, 2, 4, 3, 4, 3, 3, 2, 4, 2, 3, 3, 6, 3, 4, 2, 4, 3, 3, 2, 5, 2, 3, 3, 4, 3, 4, 2, 5, 4, 3, 2, 4, 3, 3, 3, 5, 2, 4, 3, 4, 3, 3, 3, 6, 2, 3, 4, 4, 3, 4, 3, 5, 3, 3
Offset: 1
Examples
12 = 2*2*3 so a(12)=3.
Links
- Charles R Greathouse IV, Table of n, a(n) for n = 1..1000
Crossrefs
Cf. A055642.
Programs
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Mathematica
Join[{0},Table[Total[IntegerLength[#]&/@(Flatten[Table[#[[1]],#[[2]]]&/@ FactorInteger[n]])],{n,2,120}]] (* Harvey P. Dale, Mar 10 2018 *)
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PARI
a(n)=my(f=factor(n));sum(i=1,#f[,1],#Str(f[i,1])*f[i,2]) \\ Charles R Greathouse IV, Jul 24 2012
Formula
a(n) is completely additive: a(m*n) = a(m)+a(n) for all integers m, n >= 1, with a(1)=0 and a(p^e) = e*floor(log_10(10*p)), p prime. - Diego Torres (torresvillarroel(AT)hotmail.com), Oct 26 2002
Totally additive with a(p) = A055642(p).
Extensions
a(1) added, a(40) corrected by Charles R Greathouse IV, Jul 24 2012