A076733 Largest k such that k! divides C(2n,n).
2, 3, 2, 2, 3, 3, 4, 3, 2, 2, 4, 2, 2, 5, 6, 3, 3, 3, 5, 3, 5, 5, 6, 3, 4, 4, 2, 2, 5, 2, 2, 3, 3, 3, 4, 2, 2, 5, 2, 2, 5, 5, 7, 5, 7, 7, 7, 3, 5, 4, 4, 4, 7, 5, 4, 4, 4, 5, 6, 4, 4, 4, 5, 3, 3, 3, 5, 3, 5, 5, 6, 3, 5, 5, 7, 5, 7, 7, 7, 3, 2, 2, 5, 2, 2, 7, 5, 5, 7, 2, 2, 5, 2, 2, 7, 3, 5, 5, 5, 5, 6, 5, 5, 5, 6
Offset: 1
Keywords
Links
- Robert Israel, Table of n, a(n) for n = 1..10000
Programs
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Maple
f:= proc(n) local x,k; x:= binomial(2*n,n); for k from 2 do if not (x/k!)::integer then return k-1 fi od end proc: map(f, [$1..105]); # Robert Israel, Feb 01 2019
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Mathematica
a[n_] := Module[{k = 2}, While[Divisible[Binomial[2n, n], k!], k++]; k-1]; Table[a[n], {n, 1, 105}] (* Jean-François Alcover, Oct 01 2024 *)
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PARI
a(n)=if(n<0,0,k=1; while(binomial(2*n,n)%(k!) == 0,k++); k-1)
Comments