cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A072288 Smallest prime factor of googolplex + n that exceeds 13, or 1 if googolplex + n is 13-smooth.

Original entry on oeis.org

316912650057057350374175801344000001
Offset: 1

Views

Author

Ed Pegg Jr and Robert G. Wilson v, Nov 21 2002

Keywords

Comments

a(2) is not known. After a(1) the sequence continues ?, 1429, 1129, 29, ?, 53, 427169, 5501, 19, 59, 1327, 1645318771, 61, 211, 17, 1831, ?, 43, 389, 173, 233886337, 139, 1451, 18797, 31, 37, 8297, 19, 13879, ?, 9241, 17, 29, ...
The question marks indicate terms > 10^14. - Dario Alpern, May 17 2003

Crossrefs

Programs

  • Mathematica
    (* For any individual n *) k = 17; While[ !PrimeQ[k] || PowerMod[10, 10^100, k] + n != k, k += 2]; k

Extensions

Name edited by Peter Munn, Feb 20 2025

A078813 Smallest prime factor of googol - n that exceeds 13, or 1 if googol - n is 13-smooth.

Original entry on oeis.org

1, 41, 220217, 596275259857, 17, 31, 7583, 167988019, 1898431, 19, 37, 8747, 433, 23, 4647535350279428239, 1637, 29, 1997, 569, 383, 71, 17, 179, 683592593118601, 601, 1259, 109, 47, 19, 83, 367, 43, 151, 8633431, 103, 20859069935591, 23
Offset: 0

Views

Author

Robert G. Wilson v, Dec 06 2002

Keywords

Examples

			From _Zhuorui He_, Jul 15 2025: (Start)
Googol = 10^100 = 2^100 * 5^100 is 13-smooth so a(0)=1.
10^100 - 1 = 3^2 * 11 * 41 * 101 * 251 * 271 * ... so a(1)=41. (End)
		

Crossrefs

Cf. A108251 (n such that googol - n is prime), A080197 (relates to positions of 1's).
Equivalent sequences: A076848 (googol + n), A078814 (googolplex - n).
See the formula section for the relationships with A007947, A020639, A034386.

Programs

  • PARI
    /* using M. F. Hasler's definition for A020639 */
    A078813(n)={n=10^100-n; my(p=[2,3,5,7,11,13]); for(i=1, 6, n=n/(p[i]^valuation(n,p[i]))); A020639(n)} /* Zhuorui He , Jul 17 2025 */

Formula

For n >= 1, a(n) = A020639(A007947(10^100 - n)/gcd(10^100 - n, A034386(13))), where A020639(m) = lpf(m), smallest prime factor of m. - Peter Munn, Feb 20 2025
a(-n) = A076848(n). - Zhuorui He, Jul 15 2025

Extensions

Name edited by Peter Munn, Feb 20 2025
a(0) prepended by Zhuorui He, Jul 15 2025
Showing 1-2 of 2 results.