A080637 a(n) is the smallest positive integer which is consistent with the sequence being monotonically increasing and satisfying a(1)=2, a(a(n)) = 2n+1 for n > 1.

2, 3, 5, 6, 7, 9, 11, 12, 13, 14, 15, 17, 19, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 33, 35, 37, 39, 41, 43, 45, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 96, 97, 98, 99, 100, 101, 102

Offset: 1

Author

N. J. A. Sloane and Benoit Cloitre, Feb 28 2003

Keywords

• nonn
• easy

Comments

Sequence is the unique monotonic sequence satisfying a(a(n)) = 2n+1.

Except for the first term, numbers (greater than 2) whose binary representation starts with 11 or ends with 1. - Yifan Xie, May 26 2022

Examples

			From _Yifan Xie_, May 02 2022: (Start)
a(8) = 12 because 2*2^2 <= 8 < 3*2^2, hence a(8) = 8 + 2^2 = 12;
a(13) = 19 because 3*2^2 <= 13 < 4*2^2, hence a(13) = 2*(13 - 2^2) + 1 = 19. (End)
		

Links

• Yifan Xie, Table of n, a(n) for n = 1..10000
• Benoit Cloitre, N. J. A. Sloane and M. J. Vandermast, Numerical analogues of Aronson's sequence, J. Integer Seqs., Vol. 6 (2003), #03.2.2.
• Benoit Cloitre, N. J. A. Sloane and M. J. Vandermast, Numerical analogues of Aronson's sequence, arXiv:math/0305308 [math.NT], 2003.
• Hsien-Kuei Hwang, S. Janson, and T.-H. Tsai, Exact and asymptotic solutions of the recurrence f(n) = f(floor(n/2)) + f(ceiling(n/2)) + g(n): theory and applications, Preprint, 2016.
• Hsien-Kuei Hwang, S. Janson, and T.-H. Tsai, Exact and Asymptotic Solutions of a Divide-and-Conquer Recurrence Dividing at Half: Theory and Applications, ACM Transactions on Algorithms, 13:4 (2017), #47; DOI: 10.1145/3127585.
• Index entries for sequences of the a(a(n)) = 2n family

Crossrefs

Except for first term, same as A079905. Cf. A079000.

A007378, A079905, A080637, A080653 are all essentially the same sequence.

Equals A007378(n+1)-1. First differences give A079882.

Unique monotonic sequence of positive integers satisfying a(a(n)) = k*(n-1) + 3: this sequence (k=2), A003605 (k=3), A353651 (k=4), A353652 (k=5), A353653 (k=6).

Programs

Maple

t := []; for k from 0 to 6 do for j from -2^k to 2^k-1 do t := [op(t), 4*2^k - 1 + 3*j/2 + abs(j)/2]; od: od: t;

Mathematica

b[n_] := b[n] = If[n<4, n+1, If[OddQ[n], b[(n-1)/2+1]+b[(n-1)/2], 2b[n/2]]];
a[n_] := b[n+1]-1;
a /@ Range[70] (* Jean-François Alcover, Oct 31 2019 *)

Formula

a(3*2^k - 1 + j) = 4*2^k - 1 + 3*j/2 + |j|/2 for k >= 0, -2^k <= j < 2^k.

a(2n+1) = 2*a(n) + 1, a(2n) = a(n) + a(n-1) + 1.

From Yifan Xie, May 02 2022: (Start)

For n in the range 2*2^i <= n < 3*2^i, for i >= 0:

a(n) = n + 2^i.

a(n) = 1 + a(n-1).

Otherwise, for n in the range 3*2^i <= n < 4*2^i, for i >= 0:

a(n) = 2*(n - 2^i) + 1.

a(n) = 2 + a(n-1). (End)