A081261 Start with a(1)=4; apply 4 -> 665, 5 -> 56665, 6 -> 566665; iterate.

4, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 5, 5, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 5, 5, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 5, 5, 6, 6, 6, 5, 5, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6

Offset: 1

Author

Matthew Vandermast, Mar 14 2003

Keywords

• easy
• nonn

Comments

a(n)= A081260(n) - A081260(n-1) (taking A081260(0) as equal to 0). Sum of first n terms = A081260(n).

Examples

			4 -> 665 -> 56666556666556665 -> ...
		

Crossrefs

Cf. A079000, A079948.