A081769 a(n)-th term of the continued fraction for sum(k>=0,1/2^(2^k)) is 2.

5, 13, 18, 23, 25, 30, 38, 43, 45, 53, 58, 60, 65, 70, 78, 83, 85, 93, 98, 103, 105, 110, 118, 120, 125, 133, 138, 140, 145, 150, 158, 163, 165, 173, 178, 183, 185, 190, 198, 203, 205, 213, 218, 220, 225, 230, 238, 240, 245, 253, 258, 263, 265, 270, 278, 280

Offset: 1

Author

Benoit Cloitre, Apr 09 2003

Keywords

• easy
• nonn

Examples

			The continued fraction for sum(k>=0,1/2^(2^k)) is : 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 2, 1... hence a(1)=5
		

Crossrefs

Cf. A006466, A073089.

Formula

a(n)=5*n + 0 or + 3 and it appears that a(n)=5*n+3*A073089(n+2)