A082892 Floor(q(j)), where q(j) = 2j/log(A000230(j)); log is natural logarithm, 2j-s are prime gaps > 1, A000230(j) is the minimal lesser prime opening the consecutive prime distance equals 2j.
1, 2, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 3, 3, 4, 4, 4, 4, 4, 4, 5, 5, 4, 5, 5, 5, 5, 5, 5, 5, 6, 5, 6, 6, 6, 6, 6, 7, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 7, 8, 8, 8, 7, 8, 8, 8, 9, 8, 8, 9, 8, 8, 8, 9, 10, 9, 9, 10, 9, 8, 9, 9, 9, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 9, 10, 10, 10, 10, 10, 11
Offset: 1
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Programs
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Mathematica
t=A000230 list; Table[Floor[2*j/Log[Part[t,j]]//N],{j,1,Length[t]}]
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