A084863 Number of solutions to n = 2*u^2 + 3*v^2, u*v>0.
0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 2, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 1, 0
Offset: 1
Keywords
Examples
n=770 = 2*19^2 + 3*4^2 = 2*17^2 + 3*8^2 = 2*13^2 + 3*12^2 = 2*1 + 3*16^2, therefore a(770)=4.
Links
- Eric Weisstein's World of Mathematics, Diophantine Equation: 2nd Powers.
Comments