A086593 Bisection of A086592, denominators of the left-hand half of Kepler's tree of fractions.
2, 3, 4, 5, 5, 7, 7, 8, 6, 9, 10, 11, 9, 12, 11, 13, 7, 11, 13, 14, 13, 17, 15, 18, 11, 16, 17, 19, 14, 19, 18, 21, 8, 13, 16, 17, 17, 22, 19, 23, 16, 23, 24, 27, 19, 26, 25, 29, 13, 20, 23, 25, 22, 29, 26, 31, 17, 25, 27, 30, 23, 31, 29, 34, 9, 15, 19, 20, 21, 27, 23, 28, 21, 30
Offset: 1
Keywords
Links
- Antti Karttunen, Table of n, a(n) for n = 1..2048 (computed from b-file of A020650 provided by _T. D. Noe_)
Programs
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Mathematica
(* b = A020650 *) b[1] = 1; b[2] = 2; b[3] = 1; b[n_] := b[n] = Switch[ Mod[n, 4], 0, b[n/2 + 1] + b[n/2], 1, b[(n - 1)/2 + 1], 2, b[(n - 2)/2 + 1] + b[(n - 2)/2], 3, b[(n - 3)/2]]; a[1] = 2; a[n_] := b[4 n - 4]; Array[a, 100] (* Jean-François Alcover, Jan 22 2016, after Yosu Yurramendi's formula for A020650 *)
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R
maxlevel <- 15 d <- c(1,2) for(m in 0:maxlevel) for(k in 1:2^m) { d[2^(m+1) +k] <- d[k] + d[2^m+k] d[2^(m+1)+2^m+k] <- d[2^(m+1)+k] } a <- vector() for(m in 0:maxlevel) for(k in 0:(2^m-1)) a[2^m+k] <- d[2^(m+1)+k] a[1:63] # Yosu Yurramendi, May 16 2018
Formula
From Yosu Yurramendi, Jan 04 2016: (Start)
a(2^(m+1)+k+1) - a(2^m+k+1) = A071585(k), m >= 0, 0 <= k < 2^m.
a(2^(m+2)-k) = a(2^(m+1)-k) + a(2^m-k), m > 0, 0 <= k < 2^m-1.
(End)
a(2^n) = A000045(n+3). - Antti Karttunen, Jan 29 2016, based on above.
a(2^m+k) = A071585(2^(m+1)+k), m >= 0, 0 <= k < 2^m. - Yosu Yurramendi, May 16 2018
Comments