A086843 Odd numbers m such that the sequence defined by b(1) = m; for k>1, b(k) = floor(phi*b(k-1)), where phi = (1 + sqrt(5))/2, contains only odd numbers.
1, 7, 11, 13, 17, 21, 23, 27, 33, 37, 39, 43, 49, 53, 59, 63, 65, 69, 75, 79, 81, 85, 91, 95, 101, 105, 107, 111, 117, 121, 123, 127, 131, 133, 137, 143, 147, 149, 153, 159, 163, 169, 173, 175, 179, 185, 189, 191, 195, 199, 201, 205, 211, 215, 217, 221, 227, 231
Offset: 1
Keywords
Examples
For m = 1 we get 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, ... For m = 7 we get 7, 11, 17, 27, 43, 69, 111, 179, 289, 467, 755, ...
Crossrefs
Cf. A086844.
Formula
Observation : a(n+1)-a(n) = 2, 4 or 6 for every n, a(n)=4n+O(1) and more precisely it seems that abs(a(n)-4n)<=7. Is the sequence a(n)-4n ultimately periodic ? Benoit Cloitre, Aug 10 2003