1, 1, 1, 2, 0, 1, 2, 2, 0, 1, 3, 2, 1, 0, 1, 4, 3, 2, 1, 0, 1, 5, 4, 3, 1, 1, 0, 1, 6, 7, 3, 3, 1, 1, 0, 1, 8, 8, 6, 3, 2, 1, 1, 0, 1, 10, 12, 7, 5, 3, 2, 1, 1, 0, 1, 12, 15, 11, 6, 5, 2, 2, 1, 1, 0, 1, 15, 21, 14, 10, 5, 5, 2, 2, 1, 1, 0, 1, 18, 26, 20, 12, 9, 5, 4, 2, 2, 1, 1, 0, 1, 22, 35, 25, 18, 11, 8, 5, 4, 2, 2, 1, 1, 0, 1
Offset: 1
Triangle starts:
1: 1;
2: 1, 1;
3: 2, 0, 1;
4: 2, 2, 0, 1;
5: 3, 2, 1, 0, 1;
6: 4, 3, 2, 1, 0, 1;
7: 5, 4, 3, 1, 1, 0, 1;
8: 6, 7, 3, 3, 1, 1, 0, 1;
9: 8, 8, 6, 3, 2, 1, 1, 0, 1;
10: 10, 12, 7, 5, 3, 2, 1, 1, 0, 1;
11: 12, 15, 11, 6, 5, 2, 2, 1, 1, 0, 1;
12: 15, 21, 14, 10, 5, 5, 2, 2, 1, 1, 0, 1;
13: 18, 26, 20, 12, 9, 5, 4, 2, 2, 1, 1, 0, 1;
14: 22, 35, 25, 18, 11, 8, 5, 4, 2, 2, 1, 1, 0, 1;
...
In the partition 5+2+2+2+1+1, 2 is repeated 3 times, no part is repeated more than 3 times.
From _Gary W. Adamson_, Mar 13 2010: (Start)
First few rows of the array =
...
1, 1, 1, 2, 2, 3, 4, 5, 6, 8, 10, ... = p(x)/p(x^2) = A000009
1, 1, 2, 2, 4, 5, 7, 9, 13, 16, 22, ... = p(x)/p(x^3)
1, 1, 2, 3, 4, 6, 9, 12, 16, 22, 29, ... = p(x)/p(x^4)
1, 1, 2, 3, 5, 6, 10, 13, 19, 25, 34, ... = p(x)/p(x^5)
1, 1, 2, 3, 5, 7, 10, 14, 20, 27, 37, ... = p(x)/p(x^6)
...
Finally, taking finite differences from the top and deleting the first "1", we obtain triangle A091602 with row sums = A000041 starting with offset 1:
1;
1, 1;
2, 0, 1;
2, 2, 0, 1;
3, 2, 1, 0, 1;
4, 3, 2, 1, 0, 1;
...
(End)
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