A095114 a(1)=1. a(n) = a(n-1) + (number of elements of {a(1),...,a(n-1)} that are <= n-1).
1, 2, 4, 6, 9, 12, 16, 20, 24, 29, 34, 39, 45, 51, 57, 63, 70, 77, 84, 91, 99, 107, 115, 123, 132, 141, 150, 159, 168, 178, 188, 198, 208, 218, 229, 240, 251, 262, 273, 285, 297, 309, 321, 333, 345, 358, 371, 384, 397, 410, 423, 437, 451, 465, 479, 493, 507, 522
Offset: 1
Keywords
Examples
3 elements of {a(1),...,a(4)} are <= 4, so a(5) = a(4) + 3 = 9.
Links
- Reinhard Zumkeller, Table of n, a(n) for n = 1..10000
Programs
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Haskell
a095114 n = a095114_list !! (n-1) a095114_list = 1 : f [1] 1 where f xs@(x:_) k = y : f (y:xs) (k+1) where y = x + length [z | z <- xs, z <= k] -- Reinhard Zumkeller, Feb 09 2012
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Maple
a[1]:= 1; m:= 0; for n from 2 to 100 do if a[m+1] <= n-1 then m:= m+1 fi; a[n]:= a[n-1]+m; od: seq(a[i],i=1..100); # Robert Israel, Oct 07 2015
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Mathematica
a[1]=1; a[n_]:=a[n]=a[n-1]+Length[Select[a/@Range[n-1], #
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PARI
a(n) = sum(k=1, n-1, t(k)) + 1; t(n)=local(A, t, i); if(n<3, max(0, n), A=vector(n); t=A[i=2]=2; for(k=3, n, A[k]=A[k-1]+if(t--==0, t=A[i++ ]; 1)); A[n]); vector(100, n, a(n)) \\ Altug Alkan, Oct 06 2015
Comments