cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A097872 Numerator of J(n) = A000356(n)/A000309(n) (average number of 4-colorings of rank 0 in a rooted nonseparable map which is trivalent and has 2n nodes).

Original entry on oeis.org

1, 5, 35, 147, 99, 4719, 102245, 158015, 71383, 9493939, 117578783, 81161825, 192225375, 10034164575, 176876744175, 874129996575, 506075261175, 43691164214775, 54585584382615, 91204126883805, 75171984897685, 11189060829001575, 315531515377844415, 3726508102129106091
Offset: 1

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Author

N. J. A. Sloane, Sep 21 2004

Keywords

Examples

			1, 5/4, 35/24, 147/88, 99/52, 4719/2176, 102245/41344, ...
		

Crossrefs

A295866 Number of decimal digits in the number of partitions of n.

Original entry on oeis.org

1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8
Offset: 0

Views

Author

José Hernández, Feb 13 2018

Keywords

Comments

In his book on analytic number theory, Don Newman tells this amusing story regarding the number of digits in p(n): "This is told of Major MacMahon who kept a list of these partition numbers arranged one under another up into the hundreds. It suddenly occurred to him that, viewed from a distance, the outline of the digits seemed to form a parabola! Thus the number of digits in p(n), the number of partitions of n, is around C*sqrt(n), or p(n) itself is very roughly e^(a*sqrt(n)). The first crude assessment of p(n)!"

References

  • D. J. Newman, Analytic number theory, Springer Verlag, 1998, p. 17.

Crossrefs

Programs

  • Mathematica
    Join[{1}, IntegerLength[PartitionsP[#]] & /@ Range[99]]
  • PARI
    a(n) = #digits(numbpart(n)); \\ Michel Marcus, Feb 17 2018

Formula

a(n) = A055642(A000041(n)).
Showing 1-2 of 2 results.