cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A100144 First differences of A100143.

Original entry on oeis.org

1, 2, 2, 4, 4, 4, 4, 6, 6, 6, 6, 6, 6, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 14, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 18, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22, 22
Offset: 1

Views

Author

Rick L. Shepherd, Nov 09 2004

Keywords

Comments

Each term a(n) occurs a(n) times consecutively. If duplicate terms are removed, this sequence is equivalent to A100143.
The position where values change, but also the second partial sums are in A100250. - Ralf Stephan, Aug 28 2013

Crossrefs

A118103 First differences contain a(n) n's, in order, starting with a(0)=1.

Original entry on oeis.org

1, 1, 2, 4, 6, 9, 12, 15, 18, 22, 26, 30, 34, 38, 42, 47, 52, 57, 62, 67, 72, 77, 82, 87, 93, 99, 105, 111, 117, 123, 129, 135, 141, 147, 153, 159, 166, 173, 180, 187, 194, 201, 208, 215, 222, 229, 236, 243, 250, 257, 264, 272, 280, 288, 296, 304, 312, 320, 328, 336
Offset: 0

Views

Author

Keywords

Comments

a(261) = 2701 = a(260) + 15 is the first case where a(n) is relatively prime to the difference (a(n)-a(n-1)) when that difference is composite; a(263) = 2731 is the first prime in the sequence with a composite difference.

Crossrefs

A100250 Positions where values change in A100144.

Original entry on oeis.org

1, 2, 4, 8, 14, 24, 38, 56, 78, 106, 140, 180, 226, 278, 336, 404, 482, 570, 668, 776, 894, 1022, 1160, 1308, 1466, 1638, 1824, 2024, 2238, 2466, 2708, 2964, 3234, 3518, 3816, 4128, 4454, 4794, 5148, 5520, 5910, 6318, 6744, 7188, 7650, 8130, 8628, 9144, 9678
Offset: 1

Views

Author

Rick L. Shepherd, Nov 09 2004

Keywords

Comments

Old name was "Indices of beginning terms of arithmetic progressions in A100143".
These terms are 1, A100143(1)+1, A100143(1) + A100143(2) + 1, ...; i.e., the term 1 followed by 1 + partial sums of A100143.
Second differences are in A100144. [Ralf Stephan, Aug 28 2013]

Crossrefs

Cf. A100143.

Extensions

Definition simplified by Ralf Stephan, Aug 28 2013

A364090 Add each term m of the sequence to the last one m times starting with 1, 1.

Original entry on oeis.org

1, 1, 2, 3, 5, 7, 10, 13, 16, 21, 26, 31, 36, 41, 48, 55, 62, 69, 76, 83, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 203, 216, 229, 242, 255, 268, 281, 294, 307, 320, 333, 346, 359, 375, 391, 407, 423, 439, 455, 471, 487, 503, 519, 535, 551, 567
Offset: 1

Views

Author

Wagner Martins, Jul 09 2023

Keywords

Comments

a(n) seems to grow as n^c where c is a constant with the value of approximately 1.625, in other words, lim_{n->oo} log_n(a(n)) seems to converge.

Examples

			k denotes the k-th iteration
The sequence is initialized with (1, 1)
For k = 1
Add a(1) = 1 once, you get (1, 1, 2)
For k = 2
Add a(2) = 1 once, you get (1, 1, 2, 3)
For k = 3
Add a(3) = 2 twice, you get (1, 1, 2, 3, 5, 7)
For k = 4
add a(4) = 3 three times, and you get (1, 1, 2, 3, 5, 7, 10, 13, 16)
		

Crossrefs

Cf. A100143.

Programs

  • Python
    def a_list(n):
        if n <= 2:
            return 1
        sequence = [1, 1]
        target_number_index = 0
        times_to_add = sequence[target_number_index]
        for _ in range(n - 2):
            if times_to_add == 0:
                target_number_index += 1
                times_to_add = sequence[target_number_index]
            last_term = sequence[-1]
            sequence.append(last_term + sequence[target_number_index])
            times_to_add -= 1
        return sequence
Showing 1-4 of 4 results.