cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A105374 a(n) = 4*n^3 + 4*n.

Original entry on oeis.org

0, 8, 40, 120, 272, 520, 888, 1400, 2080, 2952, 4040, 5368, 6960, 8840, 11032, 13560, 16448, 19720, 23400, 27512, 32080, 37128, 42680, 48760, 55392, 62600, 70408, 78840, 87920, 97672, 108120, 119288, 131200, 143880, 157352, 171640, 186768, 202760, 219640, 237432
Offset: 0

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Author

Henry Bottomley, Apr 02 2005

Keywords

Comments

For n > 1, the number of straight lines with n points in a 4-dimensional hypercube with n points on each edge is 4*n^3 + 12*n^2 + 16*n + 8, i.e., A105374(n+1).

Examples

			a(5) = 4*5^3 + 4*5 = 500 + 20 = 520.
		

Crossrefs

Essentially row or column of A102728 and A105374.

Programs

  • Magma
    I:=[0, 8, 40, 120]; [n le 4 select I[n] else 4*Self(n-1)-6*Self(n-2)+4*Self(n-3)-Self(n-4): n in [1..45]]; // Vincenzo Librandi, Jun 26 2012
    
  • Mathematica
    CoefficientList[Series[8*x*(1+x+x^2)/(1-x)^4,{x,0,40}],x] (* or *) LinearRecurrence[{4,-6,4,-1},{0,8,40,120},50] (* Vincenzo Librandi, Jun 26 2012 *)
  • PARI
    a(n)=4*n^3+4*n \\ Charles R Greathouse IV, Oct 16 2015

Formula

a(n) = A002522(n)*A008586(n).
G.f.: 8*x*(1 + x + x^2)/(1-x)^4. - Colin Barker, May 24 2012
a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4). - Vincenzo Librandi, Jun 26 2012
a(n) = 8*A006003(n). - Bruce J. Nicholson, Apr 18 2017
From Elmo R. Oliveira, Aug 07 2025: (Start)
E.g.f.: 4*x*(1 + x)*(2 + x)*exp(x).
a(n) = 4*A034262(n). (End)