A105647
Lexicographically earliest sequence of increasing numbers whose digits satisfy the "Fractal Jump" rule using only the digits 2 and 5: keep the first digit "d" of the sequence, then jump over the next "d" digits and keep the digit "e" on which you have landed. Jump now over the next "e" digits and keep the digit "f" on which you have landed, etc. The succession "def..." of kept digits is the sequence itself.
Original entry on oeis.org
2, 5, 25, 52, 55, 222, 252, 255, 552, 555, 2222, 5222, 5252, 5255, 22222, 22252, 22522, 22525, 22555, 25222, 52222, 55222, 55522, 55525, 55552, 55555, 222522, 225222, 225225, 225522, 252222, 252225, 522222, 2225222, 2225252, 2225255, 5222225, 5222522, 5225222
Offset: 1
The sequence and the "kept" digits begin
2, 5, 25, 52, 55, 222, 252, 255, 552, ...
^ ^ ^ ^ ^
2 5 2 5 5
A359385
The lexicographically earliest "Increasing Term Fractal Jump Sequence" that does not use the digit 0 in any terms.
Original entry on oeis.org
1, 2, 21, 22, 23, 112, 122, 132, 133, 134, 141, 221, 311, 2112, 2113, 3111, 21111, 31113, 31114, 31124, 31131, 34111, 41121, 42111, 43111, 111121, 111122, 112111, 112311, 131111, 211112, 211113, 1111311, 1111312, 3111311, 3111312, 4111131, 4111132, 4141111
Offset: 1
The sequence and the "kept" digits begin
1, 2, 21, 22, 23, 112, 122, 132, 133, ...
^ ^ ^ ^ ^ ^ ^ ^
1 2 2 1 2 2 2 3
A359611
The lexicographically earliest "Increasing Term Fractal Jump Sequence".
Original entry on oeis.org
1, 2, 20, 22, 100, 200, 201, 1000, 20000, 20001, 110000, 2000000, 2000001, 110100000, 200000000, 200000001, 1101001000000, 2000000000020, 2000000010101, 10100010000000, 20000000000002, 20020000000001, 101001010010000, 100000000200000000000000
Offset: 1
The sequence and the "kept"/"forced" digits begin
1, 2, 20, 22, 100, 200, 201, 1000, 20000, ...
^ ^ ^ ^ ^ ^ ^ ^^ ^ ^^
1 2 2 0 2 2 1 00 2 00
In the case of computing a(5), we have a 22 for a(4), so we would normally increment to 23, as there is nothing forcing the next two digits. However, since there is a 0 forcing the following digit, we must increment to the smallest number that satisfies this forced 0 (as we can't have leading zeros in a(6)).
Showing 1-3 of 3 results.
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