A106486 Number of edges in combinatorial game trees.

0, 1, 1, 2, 2, 3, 3, 4, 2, 3, 3, 4, 4, 5, 5, 6, 2, 3, 3, 4, 4, 5, 5, 6, 4, 5, 5, 6, 6, 7, 7, 8, 2, 3, 3, 4, 4, 5, 5, 6, 4, 5, 5, 6, 6, 7, 7, 8, 4, 5, 5, 6, 6, 7, 7, 8, 6, 7, 7, 8, 8, 9, 9, 10, 3, 4, 4, 5, 5, 6, 6, 7, 5, 6, 6, 7, 7, 8, 8, 9, 5, 6, 6, 7, 7, 8, 8, 9, 7, 8, 8, 9, 9, 10, 10, 11, 5, 6, 6, 7, 7

Offset: 0

Author

Antti Karttunen, May 21 2005

Keywords

• nonn

Comments

Consider the following rooted trees useful in the combinatorial game theory: each tree has zero or more subtrees at its left side and zero or more subtrees at its right side. The orientation of the subtrees among the other branches of the same side is not distinguished and all the subtrees of the same side are distinct from each other. These kinds of trees map bijectively to nonnegative integers by the following map f: f(empty tree) = 0 and f(tree with left subtrees Tl1, ..., Tlj and right subtrees Tr1, ..., Trk) = 2^(2*f(Tl1)) + ... + 2^(2*f(Tlj)) + 2^((2*f(Tr1))+1) + ... + 2^((2*f(Trk))+1). The ten game trees given on page 40 of "Winning Ways" thus translate to values Game 0 -> 0, Game 1 -> 1, Game -1 -> 2, Game 2 -> 4, Game 1/2 -> 9, Game 1/4 -> 524289, Game * -> 3, Game 1* -> 12, Game *2 -> 195, Game ^ (up) -> 129. However, this correspondence is not bijective with the computed equivalence classes of games, as many integers map to game trees with dominated or reversible options. Here a(n) gives the total number of edges in the tree f(n).

Examples

			3 = 2^0 + 2^1 = 2^(2*0) + 2^((2*0)+1) encodes the CGT tree \/ which has two edges, thus a(3)=2.
64 = 2^6 = 2^(2*3), i.e., it encodes the CGT tree
  \/
   \
which has three edges, so a(64)=3.
		

References

• E. R. Berlekamp, J. H. Conway and R. K. Guy, Winning Ways, Second Edition, Vol. 1, A K Peters, 2001, p. 40.

Crossrefs

Number of leaves: A106487, negating automorphism: A106485.