A111047 Product of continued fraction terms of H(n) = Sum_{k=1..n} 1/k.

1, 2, 5, 24, 48, 32, 100, 140, 840, 1872, 54000, 12960, 51840, 533871, 322371, 31104, 709632, 1921500, 4147200, 3701376, 124416, 262080, 2488320, 21811680, 403107840, 146966400, 2538086400, 1074954240, 14370048000, 415704960000

Offset: 1

Author

Leroy Quet, Oct 06 2005

Keywords

• nonn

Comments

The last term of each continued fraction is considered to be >= 2, for n >= 2.

Examples

			1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 = 49/20 = 2 + 1/(2 + 1/(4 + 1/2)), so the 6th term of the sequence is 2*2*4*2 = 32.
		

Crossrefs

Cf. A100398, A058027.

Programs

PARI

for(n=1,30,v=contfrac(sum(k=1,n,1/k));print1(prod(j=1,length(v),v[j]),","))

Extensions

More terms from Klaus Brockhaus, Oct 08 2005