A113471 Lucas(k)/(3k) for k = 2*3^n, where Lucas(k) is k-th Lucas number (A000032).
1, 107, 1190741689, 14769352340699478579719327005523, 253650450218391594062880777243777017638488805917392303113120204411172926964476779033181303378188721
Offset: 1
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Programs
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Mathematica
Table[ ( Fibonacci[ 2*3^n - 1 ] + Fibonacci[ 2*3^n + 1 ] ) / ( 2*3^(n+1) ), {n,1,5} ]
Formula
a(n) = ( Fibonacci[ 2*3^n - 1 ] + Fibonacci[ 2*3^n + 1 ] ) / ( 2*3^(n+1) ). a(n) = A000032[ 2*3^n ] / ( 2*3^(n+1) ).
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