cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A116598 Triangle read by rows: T(n,k) is the number of partitions of n having exactly k parts equal to 1 (n>=0, 0<=k<=n).

Original entry on oeis.org

1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 2, 1, 1, 0, 1, 2, 2, 1, 1, 0, 1, 4, 2, 2, 1, 1, 0, 1, 4, 4, 2, 2, 1, 1, 0, 1, 7, 4, 4, 2, 2, 1, 1, 0, 1, 8, 7, 4, 4, 2, 2, 1, 1, 0, 1, 12, 8, 7, 4, 4, 2, 2, 1, 1, 0, 1, 14, 12, 8, 7, 4, 4, 2, 2, 1, 1, 0, 1, 21, 14, 12, 8, 7, 4, 4, 2, 2, 1, 1, 0, 1, 24, 21, 14, 12, 8, 7, 4, 4, 2, 2, 1, 1, 0, 1
Offset: 0

Views

Author

Emeric Deutsch, Feb 18 2006

Keywords

Comments

Row sums yield the partition numbers (A000041).
Reversed rows converge to A002865. - Joerg Arndt, Jul 07 2014
T(n,k) is the number of partitions of n for which the difference between the two largest, not necessarily distinct, parts is k (in partitions having only 1 part, we assume that 0 is also a part). This follows easily from the definition by taking the conjugate partitions. Example: T(6,2) = 2 because we have [3,1,1,1] and [4,2]. - Emeric Deutsch, Dec 05 2015

Examples

			T(6,2) = 2 because we have [4,1,1] and [2,2,1,1].
Triangle starts:
00:   1,
01:   0,  1,
02:   1,  0,  1,
03:   1,  1,  0,  1,
04:   2,  1,  1,  0,  1,
05:   2,  2,  1,  1,  0,  1,
06:   4,  2,  2,  1,  1,  0,  1,
07:   4,  4,  2,  2,  1,  1,  0,  1,
08:   7,  4,  4,  2,  2,  1,  1,  0,  1,
09:   8,  7,  4,  4,  2,  2,  1,  1,  0,  1,
10:  12,  8,  7,  4,  4,  2,  2,  1,  1,  0,  1,
11:  14, 12,  8,  7,  4,  4,  2,  2,  1,  1,  0,  1,
12:  21, 14, 12,  8,  7,  4,  4,  2,  2,  1,  1,  0,  1,
13:  24, 21, 14, 12,  8,  7,  4,  4,  2,  2,  1,  1,  0,  1,
14:  34, 24, 21, 14, 12,  8,  7,  4,  4,  2,  2,  1,  1,  0,  1,
15:  41, 34, 24, 21, 14, 12,  8,  7,  4,  4,  2,  2,  1,  1,  0,  1,
...
		

Crossrefs

Programs

  • Maple
    with(combinat): T:=proc(n,k) if k
    				
  • Mathematica
    nn = 20; p = Product[1/(1 - x^i), {i, 2, nn}]; Prepend[CoefficientList[Table[Coefficient[Series[p /(1 - x y), {x, 0, nn}], x^n], {n, 1, nn}], y], 1] // Flatten  (* Geoffrey Critzer, Jan 22 2012 *)

Formula

G.f.: G(t,x) = 1/( (1-t*x)*prod(j>=2, 1-x^j ) ).
T(n,k) = p(n-k)-p(n-k-1) for kA000041).
T(n,0) = A002865(n).
Sum(k*T(n,k),k=0..n) = A000070(n-1) for n>=1.
Column k has g.f. x^k/prod(j>=2, 1-x^j ) (k>=0).