A118659 Minimum number of unit faces required to construct n unit cubes.

6, 11, 16, 20, 25, 29, 33, 36, 41, 45, 49, 52, 57, 61, 65, 68, 72, 75, 80, 84, 88, 91, 95, 98, 102, 105, 108, 113, 117, 121, 124, 128, 131, 135, 138, 141, 146, 150, 154, 157, 161, 164, 168, 171, 174, 178, 181, 184, 189, 193, 197, 200, 204, 207, 211, 214, 217, 221, 224

Offset: 1

Author

Ron R. King, May 18 2006

Keywords

• easy
• nonn

Examples

			a(2)=11 because 6 unit faces are required to construct each cube but 1 face is shared. I.e., a(2)=6+5=11.
		

Crossrefs

Cf. A117227, A270205.

Formula

a(n^3) = 3*(n^2)*(n+1) = A270205(n+1). - Mohammed Yaseen, Aug 22 2021

Extensions

Missing term a(56)=214 inserted by Mohammed Yaseen, Aug 22 2021