cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A119910 Period 6: repeat [1, 3, 2, -1, -3, -2].

Original entry on oeis.org

1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2, 1, 3, 2, -1, -3, -2
Offset: 1

Views

Author

Kartikeya Shandilya (kartikeya.shandilya(AT)gmail.com), May 28 2006

Keywords

Comments

Take any of term, multiply it to units place digit of any taken no. then save the product, then take the next term of this sequence, multiply it to the next place digit of the taken no., add the product to previous one and save it, then take the next term of the sequence, multiply it to the next place digit of the taken no. and add it to the previous sum, keep on doing this until all the digits of the taken no. are done, now if the calculated sum is divisible by 7, then the initial number taken must also be completely divisible by seven, otherwise not.
Can be converted into the sequence "10^n mod 7", 1) 1,3,2,6,4,5,1,3,2,6,4,5,1,3,2,6,4,5,1,3,2,6,4,5 .... 2) -6,-4,-5,6,4,5,-6,-4,-5,6,4,5,-6,-4,-5,6,4,5 ... 3) -6,-4,-5,-1,-3,-2,-6,-4,-5,-1,-3,-2,-6,-4,-5,-1,-3,-2 ...
Many variations can be made by adding or subtracting 7 from any term of the previous sequences. Still the divisibility rule will be valid.
Nonsimple continued fraction of (6+2*sqrt(2))/7 = 1.26120387... - R. J. Mathar, Mar 08 2012

Examples

			a(32)=?: 32%7=4, therefore a(32)=-1.
Let us test the divisibility of 342 with the series:
Take 1 from the sequence, multiply it by 2, the product is 2,
take 3 from the sequence, multiply it by 4, the product is 12,
take 2 from the sequence, multiply it by 3, the product is 6,
the sum of the products is 2 + 12 + 6 = 20,
because 20 is not divisible by 7, therefore 342 will also not be.
		

Crossrefs

Programs

Formula

From R. J. Mathar, Feb 08 2008: (Start)
O.g.f.: 2 + (3*x-2)/(x^2-x+1).
a(n) = 3*A010892(n-1) - 2*A010892(n).
a(n) = -a(n-3) for n>3. (End)
a(n) = a(n-1) - a(n-2) for n>2. - Philippe Deléham, Nov 16 2008
a(n) = (4*sqrt(3)*sin(n*Pi/3) - 6*cos(n*Pi/3))/3. - Wesley Ivan Hurt, Jun 19 2016

Extensions

New name from Omar E. Pol, Oct 31 2013