A121562 Lengths of runs of identical terms in A121561.
1, 7, 2, 4, 2, 4, 2, 2, 4, 4, 4, 2, 2, 4, 2, 2, 4, 2, 4, 4, 4, 2, 2, 4, 4, 2, 2, 2, 4, 2, 6, 2, 2, 4, 2, 4, 2, 2, 7, 2, 3, 2, 2, 2, 4, 4, 7, 1, 4, 4, 2, 4, 2, 2, 2, 4, 2, 4, 4, 7, 1, 4, 2, 4, 7, 2, 1, 2, 7, 2, 1, 2, 2, 4, 2, 2, 4, 4, 7, 1, 2, 4, 2, 4, 2, 4, 4, 4, 2, 2, 4, 7, 1, 2, 7, 2, 3, 2, 2, 4, 2, 2, 7, 2, 3
Offset: 1
Examples
a(2) = 7 because A121561 begins 0, 1, 1, 1, 1, 1, 1, 1 and the second block of identical terms is 7 ones.
Links
- Kerry Mitchell, Table of n, a(n) for n = 1..2500
Crossrefs
Cf. A121561.
Extensions
Name and example edited by M. F. Hasler, Jan 07 2019