A123223 Triangle read by rows: T(n,k) = number of ternary Lyndon words of length n with exactly k 1's.

1, 2, 1, 1, 2, 0, 2, 4, 2, 0, 3, 8, 5, 2, 0, 6, 16, 16, 8, 2, 0, 9, 32, 38, 26, 9, 2, 0, 18, 64, 96, 80, 40, 12, 2, 0, 30, 128, 220, 224, 137, 56, 13, 2, 0, 56, 256, 512, 596, 448, 224, 74, 16, 2, 0, 99, 512, 1144, 1536, 1336, 806, 332, 96, 17, 2, 0, 186, 1024, 2560, 3840, 3840

Offset: 0

Author

Mike Zabrocki, Nov 05 2006

Keywords

• nonn
• tabl

Comments

Sum of rows equal to number of ternary Lyndon words A027376 first column (k=0) is equal to the number of binary Lyndon words A001037 third through sixth column (k=2,3,4,5) equal to A124720, A124721, A124722, A124723 T(n+1,n-1) entry equal to A042948.

Examples

			Triangle begins:
   1;
   2,  1;
   1,  2,  0;
   2,  4,  2,  0;
   3,  8,  5,  2,  0;
   6, 16, 16,  8,  2,  0;
   9, 32, 38, 26,  9,  2, 0;
  18, 64, 96, 80, 40, 12, 2, 0;
T(n,1) = 2^(n-1) because all words beginning with a 1 and consisting of the rest 2's or 3's are ternary Lyndon words with exactly one 1.
		

Links

• Alois P. Heinz, Rows n = 0..140, flattened.

Crossrefs

Cf. A027376, A001037, A124720, A124721, A124722, A124723, A051168, A042948.

Formula

G.f. for columns (except for k=0) given by 1/k*Sum_{d|k} mu(d) x^k/(1-2*x^d)^(k/d) T(0,0) = 1 and T(n,0) = 1/n*Sum_{d|n} mu(d)*2^(n/d) T(n,n) = 0 if n>1, T(n,n-1) = 2.