A124289 Unstable twins = pairs of consecutive numbers in A124288 (indices of unstable zeros of the Riemann zeta function).
78, 79, 218, 219, 234, 235, 299, 300, 370, 371, 500, 501
Offset: 1
Examples
The consecutive zeros rho78 and rho79 of zeta(s,1) on the line Re(s) = 1/2 connect by paths of zeros of zeta(s,a) to zeros of zeta(s,1/2) on the line Re(s) = 0, so rho78 and rho79 are "unstable twins," and 78 and 79 are members.
References
- M. Trott, Zeros of the Generalized Riemann Zeta Function zeta(s,a) as a Function of a, background image in graphics gallery, in S. Wolfram, The Mathematica Book, 4th ed. Cambridge, England: Cambridge University Press, 1999, p. 982.
- M. Trott, The Mathematica GuideBook for Symbolics, Springer-Verlag, 2006, see "Zeros of the Hurwitz Zeta Function".
Links
- A. Fujii, Zeta zeros, Hurwitz zeta functions and L(1,Chi), Proc. Japan Acad. 65 (1989), 139-142.
- R. Garunkstis and J. Steuding, On the distribution of zeros of the Hurwitz zeta-function, Math. Comput. 76 (2007), 323-337.
- R. Garunkstis and J. Steuding, Questions around the Nontrivial Zeros of the Riemann Zeta-Function. Computations and Classifications, Math. Model. Anal. 16 (2011), 72-81.
- J. Sondow and Eric Weisstein's World of Mathematics, Hurwitz Zeta Function
- M. Trott, Zeros of the Generalized Riemann Zeta Function zeta(s,a) as a Function of a
Formula
Solve the differential equation ds(a)/da = -(dzeta(s,a)/da)/(dzeta(s,a)/ds) = s*zeta(s+1,a)/(dzeta(s,a)/ds) where s = s0(a) and zeta(s0(a),a) = 0. For initial conditions use the zeros of zeta(s,1).
Extensions
Corrected by Jonathan Sondow, Nov 10 2006, using more accurate calculations by R. Garunkstis and J. Steuding.
Comments