A127859 a(n) = r(A127858(n)), where r if the cyclic replacement map of the digits d of n in base 12 defined by d->d+1 if d<11 and d->0 if d=11.

7, 79, 943, 11311, 135727, 1628719, 19544623, 234535471, 2814425647, 33773107759, 405277293103, 4863327517231, 58359930206767, 700319162481199, 8403829949774383, 100845959397292591, 1210151512767511087

Offset: 1

Author

Walter Kehowski, Feb 04 2007

Keywords

• nonn
• base

Comments

In base 12 the sequence is 7, 67, 667, 6667, 66667, 666667, 6666667, 66666667, 666666667, 6666666667.

Examples

			a(2)=66 since, in base 12, 66=56, r(56)=67 and r(56^2)=r(2630)=3741=67^2.
In base 12, a(2)=r(A127858(2))=r(56)=67. In base 10, 67 is 79.
		

Crossrefs

Cf. A117755, A127856, A127857, A127858, A127860, A127861, A192544.

Formula

a(n) = 6*(12^n - 1)/11 + 1. - Max Alekseyev, Jul 27 2023

Extensions

More terms from Max Alekseyev, Jul 27 2023