A131439 Inverse binomial transform of A131438 (assuming zero offset in both sequences).

1, 7, 14, 18, 22, 26, 30, 34, 38, 42, 46, 50, 54, 58, 62, 66, 70, 74, 78, 82, 86, 90, 94, 98, 102, 106, 110, 114, 118, 122, 126, 130, 134, 138, 142, 146, 150, 154, 158, 162, 166, 170, 174, 178, 182

Offset: 1

Author

Gary W. Adamson, Jul 11 2007

Keywords

• nonn

Comments

Conjecture: The sequence appears to be (1, 7, ...) followed by 4k + 14; k=0,1,2,...; thus: (1, 7, 14, 18, 22, 26, ...).

Inverse binomial transform of this sequence = (1, 6, 1, -4, 7, -10, 13, -16, 19, -22, ...).

Examples

			(1, 3, 3, 1) dot (1, 7, 14, 18) = 82 = A131438(4).
		

Crossrefs

Cf. A131436, A131437, A131438.

Formula

A007318^(-1) * A131438.

a(n) = 2*a(n-1) - a(n-2) for n>4. G.f.: -x*(x+1)*(3*x^2-4*x-1) / (x-1)^2. [Colin Barker, Jan 06 2013]