A132424 a(0)=1 and, for n>0, a(n)=a(Floor((n-1)/a[n-1]))+2.
1, 3, 3, 3, 5, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 7, 5, 7, 5, 7, 5, 5, 5, 5, 5, 7, 7, 7, 7, 7, 5, 7, 5, 7, 5, 7, 5, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7
Offset: 0
Keywords
Links
- N. J. A. Sloane, Table of n, a(n) for n = 0..20000
Programs
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Maple
a[0]:=1: for n from 1 to 20000 do a[n]:=2+a[floor((n-1)/a[(n-1)])] end do: # N. J. A. Sloane, May 15 2017
Comments