A133987 a(n) = A005704( (3^n + (-1)^n - 2)/4 ), where A005704(n) = number of partitions of 3n into powers of 3.
1, 1, 3, 12, 117, 2250, 107352, 12298500, 3613136949, 2742962912055, 5503085134707267, 29497134965411187747, 427365985177386403469028, 16883252883454411208147060304, 1832920589508888783152391724736550
Offset: 0
Keywords
Examples
Let b(n) = A005704(n) = number of partitions of 3n into powers of 3, then the initial terms of this sequence begin: b(0), b(0), b(2), b(6), b(20), b(60), b(182), b(546), b(1640),... APPLICATION: SPECIAL TERNARY TREE. a(n) = number of nodes in generation n of the following tree. Start at generation 0 with a single root node labeled [1]. From then on, each parent node [k] is attached to k child nodes with labels congruent to 1(mod 3) for even n, or 3(mod 3) for odd n, within the range {1..3k}, for generation n >= 0. The initial generations 0..4 of the tree are as follows; the path from the root node is given, followed by child nodes in []. GEN.0: [1]; GEN.1: 1->[3]; GEN.2: 1-3->[1,4,7]; GEN.3: 1-3-1->[3] 1-3-4->[3,6,9,12] 1-3-7->[3,6,9,12,15,18,21]; GEN.4: 1-3-1-3->[1,4,7] 1-3-4-3->[1,4,7] 1-3-4-6->[1,4,7,10,13,16] 1-3-4-9->[1,4,7,10,13,16,19,22,25] 1-3-4-12->[1,4,7,10,13,16,19,22,25,28,31,34] 1-3-7-3->[1,4,7] 1-3-7-6->[1,4,7,10,13,16] 1-3-7-9->[1,4,7,10,13,16,19,22,25] 1-3-7-12->[1,4,7,10,13,16,19,22,25,28,31,34] 1-3-7-15->[1,4,7,10,13,16,19,22,25,28,31,34,37,40,43] 1-3-7-18->[1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49,52] 1-3-7-21->[1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46,49,52,55,58,61] . Note: the sum of the labels in generation n equals a(n+1) and the largest term in generation n = (3^(n+1) + (-1)^(n+1) - 2)/4 + 1.
Links
- Alois P. Heinz, Table of n, a(n) for n = 0..40
Programs
Formula
(3^n + (-1)^n - 2)/4 gives the n-th number that has alternating base-3 digits {0,2} (starting with zero).