A135810 Number of coincidence-free length n lists of 4-tuples with all numbers 1..n in tuple position k, for k=1..4.
1, 0, 15, 1250, 326685, 205713924, 267499350955, 643364455632870, 2637753876195952185, 17316358344270678304520, 173227930768100416550798151, 2536860701329458663625695526890
Offset: 0
Examples
4-tuple combinatorics: a(1)=0 because the only list of 4-tuples composed of 1 is [(1,1,1,1)] and this is a coincidence for j=1. 4-tuple combinatorics: from the 2^4 possible 4-tuples of numbers 1 and 2 all except (1,1,1,1) appear as first members of the length 2 lists. The second members are the 4-tuples obtained by interchanging 1 and 2. E.g., one of the a(2)=15 lists is [(1,1,1,2),(2,2,2,1)]. The list [(1,1,1,1),(2,2,2,2)] does not qualify because it has in fact two coincidences, those for j=1 and j=2.
References
- Ch. A. Charalambides, Enumerative Combinatorics, Chapman & Hall/CRC, Boca Raton, Florida, 2002, p. 187, Exercise 13.(a), for r=4.
Links
- G. C. Greubel, Table of n, a(n) for n = 0..143
Programs
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Mathematica
Table[Sum[(-1)^k Binomial[n,k](n-k)!^4,{k,0,n}],{n,0,11}] (* Geoffrey Critzer, Jun 17 2013 *)
Formula
a(n) = Sum_{j=0..n} ( ((-1)^(n-j))*binomial(n,j)*(j!)^4 ). See the Charalambides reference a(n) = B_{n,4}.
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