A135811 Number of coincidence-free length n lists of 5-tuples with all numbers 1..n in tuple position k, for k=1..5.
1, 0, 31, 7682, 7931709, 24843464324, 193342583284315, 3250662144028779654, 106536051676371091349113, 6291424280473807580386161416, 629175403160580417773688864819351, 101332539752812925263300043667901615370, 25215284734588360186537964188340607229390261
Offset: 0
Examples
5-tuple combinatorics: a(1)=0 because the only list of 5-tuples composed of 1 is [(1,1,1,1,1)] and this is a coincidence for j=1. 5-tuple combinatorics: from the 2^5 possible 5-tuples of numbers 1 and 2 all except (1,1,1,1,1) appear as first members of the length 2 lists. The second members are the 5-tuples obtained by interchanging 1 and 2 in the first member. E.g. one of the a(2) = 2^5-1 = 31 lists is [(1,1,1,1,2),(2,2,2,2,1)]. The list [(1,1,1,1,1),(2,2,2,2,2)] does not qualify because it has in fact two coincidences, those for j=1 and j=2.
References
- Ch. A. Charalambides, Enumerative Combinatorics, Chapman & Hall/CRC, Boca Raton, Florida, 2002, p. 187, Exercise 13.(a), for r=5.
Links
- G. C. Greubel, Table of n, a(n) for n = 0..100
Programs
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Mathematica
Table[Sum[(-1)^(n - k)*Binomial[n, k]*(k!)^5, {k, 0, n}], {n,0,25}] (* G. C. Greubel, Nov 23 2016 *)
Formula
a(n) = Sum_{j=0..n} ((-1)^(n-j))*binomial(n,j)*(j!)^5. See the Charalambides reference a(n)=B_{n,5}.
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