A135813 Number of coincidence-free length n lists of 7-tuples with all numbers 1..n in tuple position k, for k=1..7.
1, 0, 127, 279554, 4585352445, 358295150440964, 100303980203191474555, 82605709118517742843295238, 173237539725464803175622157326841, 828591383820135935294977528049328110600, 8285921143688038883760817278192753357365412471
Offset: 0
Examples
7-tuple combinatorics: a(1)=0 because the only list of 7-tuples composed of 1 is [(1,1,1,1,1,1,1)] and this is a coincidence for j=1. 7-tuple combinatorics: from the 2^7=128 possible 7-tuples of numbers 1 and 2 all except (1,1,1,1,1,1,1) appear as first members of the length 2 lists. The second members are the 7-tuples obtained by interchanging 1 and 2 in the first member. E.g. one of the a(2) = 2^7-1 = 127 lists is [(1,1,1,1,1,1,2),(2,2,2,2,2,2,1)]. The list [(1,1,1,1,1,1,1),(2,2,2,2,2,2,2)] does not qualify because it has in fact two coincidences, those for j=1 and j=2.
References
- Ch. A. Charalambides, Enumerative Combinatorics, Chapman & Hall/CRC, Boca Raton, Florida, 2002, p. 187, Exercise 13.(a), for r=7.
Links
- G. C. Greubel, Table of n, a(n) for n = 0..90
Crossrefs
Cf. A135812 (coincidence-free 6-tuples).
Programs
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Mathematica
Table[Sum[(-1)^(n - k)*Binomial[n, k]*(k!)^7, {k, 0, n}], {n,0,25}] (* G. C. Greubel, Nov 23 2016 *)
Formula
a(n) = Sum_{j=0..n} ((-1)^(n-j))*binomial(n,j)*(j!)^7. See the Charalambides reference a(n)=B_{n,7}.
Comments